Lab Report 3
.docx
keyboard_arrow_up
School
University of Miami *
*We aren’t endorsed by this school
Course
MISC
Subject
Electrical Engineering
Date
Apr 3, 2024
Type
docx
Pages
6
Uploaded by JusticeAntelope4727 on coursehero.com
Name:
Partner(s):
C-Number:
Lab-Section:
Lab 5
Lab 3
Tristan Loftus – C23782283
Partners: Jasem & Abdulaziz Part 1 Diode Current-Voltage Characteristics Forward Biased Connection
Reversed Biased Connection
Part 1.b
Measured Resistance of R
(
W
)
2.2 K Part 1. d
Part 1. e
V
s
(V)
V
D
(V)
V
R
(V)
I
D
= V
R
/R (mA)
V
D
(V)
V
R
(V)
I
D = V
R
/R (mA)
0
0
0
0
-0.26
0.01
4.54545E-06
0.1
0.113
0
0
-0.117
0.01
4.54545E-06
0.2
0.194
0.05
2.27E-05
-0.212
0.01
4.54545E-06
0.3
0.319
0.06
2.72E-05
-0.294
0.01
4.54545E-06
0.4
0.377
0.138
0.00006273
-0.409
0.01
4.54545E-06
0.5
0.439
0.082
0.000037273
-0.511
0.01
4.54545E-06
0.6
0.462
0.155
0.000070455
-0.6
0.01
4.54545E-06
0.7
0.48
0.245
0.000111364
-0.71
0.01
4.54545E-06
0.8
0.491
0.325
0.000147727
-0.82
0.01
4.54545E-06
0.9
0.5
0.402
0.000182727
-0.9
0.01
4.54545E-06
1
0.508
0.483
0.000219545
-1.03
0.01
4.54545E-06
1.2
0.52
0.68
0.000309
-1.2
0.01
4.54545E-06
1.4
0.532
0.84
0.000382
-1.41
0.01
4.54545E-06
1.6
0.542
1.04
0.000473
-1.65
0.01
4.54545E-06
1.8
0.55
1.26
0.000573
-1.8
0.01
4.54545E-06
2
0.56
1.45
0.000659
-2
0.01
4.54545E-06
2.2
0.56
1.64
0.000745
-2.21
0.01
4.54545E-06
2.4
0.57
1.85
0.000841
-2.4
0.01
4.54545E-06
2.6
0.57
2
0.000909
-2.6
0.01
4.54545E-06
2.8
0.58
2.23
0.001014
-2.8
0.01
4.54545E-06
3
0.58
2.42
0.0011
-3
0.01
4.54545E-06
3.2
0.58
2.65
0.001205
-3.2
0.01
4.54545E-06
3.4
0.59
2.83
0.001286
-3.4
0.01
4.54545E-06
3.6
0.59
3
0.001364
-3.6
0.01
4.54545E-06
3.8
0.59
3.2
0.001455
-3.8
0.01
4.54545E-06
4
0.59
3.4
0.001545
-4
0.01
4.54545E-06
4.2
0.6
3.6
0.001636
-4.2
0.01
4.54545E-06
4.4
0.6
3.8
0.001727
-4.4
0.01
4.54545E-06
4.6
0.6
4
0.001818
-4.6
0.01
4.54545E-06
4.8
0.6
4.21
0.001914
-4.8
0.01
4.54545E-06
5
0.6
4.42
0.002009
-5
0.01
4.54545E-06
Part 1.f
Name:
Partner(s):
C-Number:
Lab-Section:
Lab 5
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0
0
0
ID
Voltage of Diode
Current of Diode
Unable to form exponential trendline, due to there being 0 values in data. Part 2 LED Forward Biasing
Part 2.a - Led requirements (expected values):
V
D = 1.64V
What resistor value should you use?
I
D
= 1.45mA
Part 2.c
Name:
Partner(s):
C-Number:
Lab-Section:
Lab 5
Part 2.d through 2.e
Component
Measured Resistance (
W
)
Measured Voltage (V)
Current (mA)
I
D
=V
R
/R
R
2.2 k 3.37
1.53 LED
N/A
1.65 V
1.53
V
S
N/A
5
1.53
*Comment on differences between expected and measured values The measured voltage of the diode is the same as the expected voltage. The current running through the circuit is slightly larger compared to the expected current because of what resistor is used. The measured voltage of the resistor can vary as the value of the resistor itself can vary. By dividing the measured voltage by the value of the resistor you can determine the current running through the resistor. Since the circuit is built in series the current is the same through all the components.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Questions
H.W: Determine Vo and ID for the circuit in figure
below after adding a resistance of 2kQ in series
with both diodes
+20 V
Si
St
4.7 ks2
arrow_forward
Challenging Diodes problem I'm stuck on: In the circuit below, Vz = Vz0 = 5 v. rz = 0 and Iz,min = 0.
What is the current through the diode, voltage drop measured V1 and is the diode on in each case?
a) Vin = -5
b) Vin = 5
c) Vin = 15
arrow_forward
Determine the minimum and the maximum input voltages that can be regulated by the Zener diode shown
in figure 5. From data sheet the Zener diode has the following values:
Vz=9.5 V at IZ1=65 mA, IzK =5.5 mA, PDmaxN)=1.25 W, and Z, = 15 N .
R
Vout
650 Q
Vin
4 Vz
Figure 5
arrow_forward
Determine which diodes are forward-biased and which are reverse-biased in the configurations
shown in Figure 4. Assuming a 0.7-V drop across each forward-biased diode, determine the output
voltage.
O+5 V
-10 V
R
DI
+s vOK
D,
-SVOKH
D3
+s vOK
D4
-5 voK
DI
-5VOK
Dz
OVout
OVout
+5 voK
Figure 4.
arrow_forward
Consider the Zener diode circuit shown in Figure. The Zener Breakdown Voltage (Vz) is 5.6 V at Iz=
0.1mA. Zener resistance is rz= 10 0. What is Vo without load (RL= ) ?
R= 0.5 ko
Vo
R
Vps= 10 V
arrow_forward
In the circuit shown in the figure;
B) When RL = 1Kohm and capacitor C is deactivated, draw VA and V0 in scale according to input voltage Vs. NOTE = diodes are ideal
arrow_forward
Determine the minimum and the maximum input voltages that can be regulated by the Zener diode shown
in figure 5. From data sheet the Zener diode has the following values:
Vz -9.5 V at IzT =65 mA, IZK =5.5 mA, PDumax)= 1.25 W, and Zz 15 Q.
Vout
650 Q
Vin
AVz
Figure 5
arrow_forward
B. For the circuit shown below, assume that the zener diode has Vz-3.3V and rz=092 when
reverse biased, and has a 0.7V drop when forward biased. Fill the following table for
values of Vo for different values of input voltage Vi.
R1
Vi
Vi
-8V
OV
8V
1k
5V
N
V2
R21k
Vo
Vo
arrow_forward
Consider the following circuit:
VI
R₁ = 4kQ2
IDI
R₂ =
8 ΚΩ
D₁
ID2
R3 =
6 ΚΩ
D2
ID3
+
1.0 V
-
VO
R4=
4 ΚΩ
D3
+
2.0 V
Figure 1: Diode circuit for the Question
Please find Ip1, ID2, IDs and to using constant voltage drop model for
diodes. UF 0.7 V. v1 = 3V.
arrow_forward
After replacing R5 with diode IN4007 (switch K3 to diode side) .What conclusion can you draw from analysis of this step ?
arrow_forward
In the Figure as shown below the
current (I) will be equal to:
----
Assume that all diodes are silicon
-practical diode model
4 KUZ
lovt
32 KSL
2.2 mA O
2.3 mA O
2.4 mA O
1.1 mA O
arrow_forward
In the circuit shown in the figure; A) When RL = 5Kohm and capacitor C is switched on, draw VA and V0 in scale according to input voltage Vs.
NOTE = diodes are ideal
arrow_forward
Q4)
Determine and sketch the output voltage across the load resistor (RL) for the circuit shown below.
(assume Si diodes)
V_DC
0.75
0.25
V_SIN
Y SIN
as
RL
-1
v SOR
V_SQR
0.75
-0.75
V_TRI
V TRI
as
arrow_forward
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit
below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant
voltage model. The smoothing capacitor value is equal to
220V ams
5OHZ
İL-DC =05A
RL VL-DC =20V
arrow_forward
In Figure-1 (a and b), calculate the load current, load voltage, load power, diode power, and total
power using 3d approximation if Rp 802 and diode current is 10 mA.
Note please solve within 30 minutes.avoid plagiarism
arrow_forward
For the following bridge rectifier circuit, assume Vm = 5 V. Analyze the circuit and plot the
waveshape Vo (t) as a function of time for one full cycle. Show all supporting circuit diagrams as
required. Compute Vde (V). The diodes are ideal diodes.
Võ
Vm
The
PI
D2
Vo
- Vm
2. 2h2
2-22
(2.2ks)
2.212
arrow_forward
Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit
below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant
voltage model. The smoothing capacitor value is equal to
IL-DC =0:5A
RL VL-DC =20V
220V omsb
O 001 F
O 0.02 F
O 0.0167F
O None of the above
Activate
arrow_forward
6:1
D3
Vin
RL
D4
50 Hz
D2
560 2
Figure 2
(b) The full-wave bridge rectifier in Figure 2 has 170 V ms sinusoidal input at the primary circuit.
Di, D2, Ds and D4 are practical Si diodes and each has barrier potential (V3) of 0.7 V.
(1) Determine Vplin), Vpígri, Vplcec) and VpRL).
(ii) Draw waveforms for Vn, Veri, Vze and Vau for TWO (2) complete input cycles.
(ii) Calculate Vavo and peak inverse voltage (PIV).
(iv) Calculate the maximum current flowing through each diode.
lle
arrow_forward
Q3) For the circuit in figure(2) find the current and the voltage for (1k Ohm, 2k Ohm, 3k Ohm) and the
voltage on each diode where each diodes are Ge-type:
D1
D4
1k Ohm
D2
D5
-21 V
2k Ohm
D6
-14 V
12V
3k Ohm
arrow_forward
As shown is a positive parallel clipper circuit which has an input voltage of E=t5V. The negative output voltage is to be -4.5V when lo is 5mA. Assume ideal diode model approximation.
Determine the value of R1 in ohms.
Note: Write only the numeric value of the answer, round to 4 decimal places. No need to include the unit.
R,
+E
ww
Output
Input
D,
-E
-(E-1,R,)
arrow_forward
In the circuit shown in the figure, draw vx and v0 with a scale according to the input voltages. note = R1 = 10Kohm R2 = 1kohm R3 = 1Kohm, threshold voltages of diodes shall be VE = 0.7V.
arrow_forward
2-3 DIODE MODELS
1. Determine whether each silicon diode in the figure is forward-biased
or reverse-biased.
2. Determine the voltage across each diode in figure, assuming the
practical model.
3. Determine the voltage across each diode in figure, assuming an ideal
diode.
4. Determine the voltage across each diode in figure, using the
complete diode model with r'a= 102 and r'R = 1002.
100 V
+
10 Ω
5 V
560 N
8 V
(a)
(b)
10 kN
10 kN
1.0 kM 1.5 kN
4.7 kN
30 V
10 V
20 V
4.7 kN
(c)
(d)
arrow_forward
In the figure below, calculate the following (use the second diode approximation):
Np: N₂
6:1
Vp
120 Vac
60 Hz
(a) Vs
(b) Vout(pk)
(c) Vdc
rü
D₁
D₂
Vout
R₁-2000)
(d) IL
(e) PIV of the diodes
(f) fout
arrow_forward
Consider the same circuit again. Vz= 4V.
10V
6V
R2
R3
+ V
R1
R
R1 = 10k2 and R2 = R3 = 6kQ. Guess that the diode is OFF. What is the minimum
value of R that causes the diode to be in Zener breakdown? Enter your answer in kQ
rounded to one decimal place.
Hint: Guess that the diode is OFF, determine Va and Vb, then check the conditions
for the diode not to be in Zener breakdown.
arrow_forward
Draw the input waveform and output waveform for the circuit given below with proper values marked in the
figure. Assume D1 as germanium and D2 as silicon diodes. Input Vpp=20V, V1=5 v and V2=8 V.
R
DZ
D1
Vin
Vout
V2
Maximum voltage of output waveform
Minimum voltage of output waveform
Windows hui
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Related Questions
- H.W: Determine Vo and ID for the circuit in figure below after adding a resistance of 2kQ in series with both diodes +20 V Si St 4.7 ks2arrow_forwardChallenging Diodes problem I'm stuck on: In the circuit below, Vz = Vz0 = 5 v. rz = 0 and Iz,min = 0. What is the current through the diode, voltage drop measured V1 and is the diode on in each case? a) Vin = -5 b) Vin = 5 c) Vin = 15arrow_forwardDetermine the minimum and the maximum input voltages that can be regulated by the Zener diode shown in figure 5. From data sheet the Zener diode has the following values: Vz=9.5 V at IZ1=65 mA, IzK =5.5 mA, PDmaxN)=1.25 W, and Z, = 15 N . R Vout 650 Q Vin 4 Vz Figure 5arrow_forward
- Determine which diodes are forward-biased and which are reverse-biased in the configurations shown in Figure 4. Assuming a 0.7-V drop across each forward-biased diode, determine the output voltage. O+5 V -10 V R DI +s vOK D, -SVOKH D3 +s vOK D4 -5 voK DI -5VOK Dz OVout OVout +5 voK Figure 4.arrow_forwardConsider the Zener diode circuit shown in Figure. The Zener Breakdown Voltage (Vz) is 5.6 V at Iz= 0.1mA. Zener resistance is rz= 10 0. What is Vo without load (RL= ) ? R= 0.5 ko Vo R Vps= 10 Varrow_forwardIn the circuit shown in the figure; B) When RL = 1Kohm and capacitor C is deactivated, draw VA and V0 in scale according to input voltage Vs. NOTE = diodes are idealarrow_forward
- Determine the minimum and the maximum input voltages that can be regulated by the Zener diode shown in figure 5. From data sheet the Zener diode has the following values: Vz -9.5 V at IzT =65 mA, IZK =5.5 mA, PDumax)= 1.25 W, and Zz 15 Q. Vout 650 Q Vin AVz Figure 5arrow_forwardB. For the circuit shown below, assume that the zener diode has Vz-3.3V and rz=092 when reverse biased, and has a 0.7V drop when forward biased. Fill the following table for values of Vo for different values of input voltage Vi. R1 Vi Vi -8V OV 8V 1k 5V N V2 R21k Vo Voarrow_forwardConsider the following circuit: VI R₁ = 4kQ2 IDI R₂ = 8 ΚΩ D₁ ID2 R3 = 6 ΚΩ D2 ID3 + 1.0 V - VO R4= 4 ΚΩ D3 + 2.0 V Figure 1: Diode circuit for the Question Please find Ip1, ID2, IDs and to using constant voltage drop model for diodes. UF 0.7 V. v1 = 3V.arrow_forward
- After replacing R5 with diode IN4007 (switch K3 to diode side) .What conclusion can you draw from analysis of this step ?arrow_forwardIn the Figure as shown below the current (I) will be equal to: ---- Assume that all diodes are silicon -practical diode model 4 KUZ lovt 32 KSL 2.2 mA O 2.3 mA O 2.4 mA O 1.1 mA Oarrow_forwardIn the circuit shown in the figure; A) When RL = 5Kohm and capacitor C is switched on, draw VA and V0 in scale according to input voltage Vs. NOTE = diodes are idealarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Electricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage LearningDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning