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1. Suppose you mix 21.0 g of water at 52.7° C with 54.9 g of water at 31.5° C in an insulated cup. What is the maximum temperature of the water after mixing?

1. Suppose you mix 21.0 g of water at 52.7° C with 54.9 g of water at 31.5° C in an insulated cup. What is the maximum temperature of the water after mixing?

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.104QP: Suppose you mix 23.6 g of water at 66.2C with 45.4 g of water at 35.7C in an insulated cup. What is...
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Heat and Enthalpy Solved Problems 1. Suppose you mix 21.0 g of water at 52.7° C with 54.9 g of water at 31.5° C in an insulated cup. What is the maximum temperature of the water after mixing? Answer: Asystem = -4surroundings Яhot H,0 — -Ясоol H20 Тhot H,0Chot н,047hot H,0 3 -тсоol H20Ссol H,047cоol H,0 >(4.184)aTnot H,0 = -(54.9 g) (4.184 ) AThot H,0 =- ΔΙ cool H2O °C 87.86 )ATrot Hz0 = (229.702) ATe сool Hz0 AThot H,0 = (2.614)ATcool H20 Tf - 52.7°C = 2.614T; – 31.5°C 2.614T; : = 21.2°C Tf = = 8.11°C Heat and Enthalpy Solved Problems 2. Use the information provided to determine AH°rxn for the following reaction 3 Fe203 (s) + CO (g) → 2 Fe304 (s) + CO2 (g) ΔΗ ? rxn ΔΗ' Fe203 (s) Fe304 (s) CO (g) CO2 (g) -824 kJ/mol -1118 kJ/mol -111 kJ/mol -394 kJ/mol Answer: kJ (-824- mol kJ + -111 mol) kJ 1118· mol kJ + -394. mol) kJ 577 mol
Transcribed Image Text:Heat and Enthalpy Solved Problems 1. Suppose you mix 21.0 g of water at 52.7° C with 54.9 g of water at 31.5° C in an insulated cup. What is the maximum temperature of the water after mixing? Answer: Asystem = -4surroundings Яhot H,0 — -Ясоol H20 Тhot H,0Chot н,047hot H,0 3 -тсоol H20Ссol H,047cоol H,0 >(4.184)aTnot H,0 = -(54.9 g) (4.184 ) AThot H,0 =- ΔΙ cool H2O °C 87.86 )ATrot Hz0 = (229.702) ATe сool Hz0 AThot H,0 = (2.614)ATcool H20 Tf - 52.7°C = 2.614T; – 31.5°C 2.614T; : = 21.2°C Tf = = 8.11°C Heat and Enthalpy Solved Problems 2. Use the information provided to determine AH°rxn for the following reaction 3 Fe203 (s) + CO (g) → 2 Fe304 (s) + CO2 (g) ΔΗ ? rxn ΔΗ' Fe203 (s) Fe304 (s) CO (g) CO2 (g) -824 kJ/mol -1118 kJ/mol -111 kJ/mol -394 kJ/mol Answer: kJ (-824- mol kJ + -111 mol) kJ 1118· mol kJ + -394. mol) kJ 577 mol
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