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1..eafor the process that ammonia (NH, MW=17) is used as refrigerant for cooling. Find the Joule- Thomson coefficient Hu = LQT/P Ju (in °R/psia) at T1 = 490°R and P1 =80 psia. You can use the van der Waals equation of state. P = RI v-b a and M== 1 RT (v - b) RT （v-6）” 2a v - V The thermodynamic data for ammonia are: a= 15847.6 (psia)(ft*) /(Ubmol), b= 0.5988 ft'/Ibmal, R = 10.73 (psia)(ft*)/(UbmaliR), (R= 4.386 Btu/(lbmoliR). And molar volume y = 63.22 ft'/lomol (at the given T1, Pi above).

1..eafor the process that ammonia (NH, MW=17) is used as refrigerant for cooling. Find the Joule- Thomson coefficient Hu = LQT/P Ju (in °R/psia) at T1 = 490°R and P1 =80 psia. You can use the van der Waals equation of state. P = RI v-b a and M== 1 RT (v - b) RT （v-6）” 2a v - V The thermodynamic data for ammonia are: a= 15847.6 (psia)(ft*) /(Ubmol), b= 0.5988 ft'/Ibmal, R = 10.73 (psia)(ft*)/(UbmaliR), (R= 4.386 Btu/(lbmoliR). And molar volume y = 63.22 ft'/lomol (at the given T1, Pi above).

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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1..eafor the process that ammonia (NH, MW=17) is used as refrigerant for cooling. Find the Joule- Thomson coefficient Hu = LQT/P Ju (in °R/psia) at T1 = 490°R and P1 =80 psia. You can use the van der Waals equation of state. P = RI v-b a and M== 1 RT (v - b) RT （v-6）” 2a v - V The thermodynamic data for ammonia are: a= 15847.6 (psia)(ft*) /(Ubmol), b= 0.5988 ft'/Ibmal, R = 10.73 (psia)(ft*)/(UbmaliR), (R= 4.386 Btu/(lbmoliR). And molar volume y = 63.22 ft'/lomol (at the given T1, Pi above).
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