13.1 The settled sludge from coagulation of a surface water is 1.5% solids, of which 30% arevolatile. Compute the specific gravity of the dry solids and specific gravityfor the fixed matter andsludge. Assume specific gravity values of 2.5What is the volume of waste in cubic meters per 1000 kg of dry solids?of the wet1.0 for the volatile.

The objective of the question is to calculate the specific gravity of the dry solids, the specific…

Answered: 13.1 The settled sludge from…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A coagulation treatment plant with a flow of 0.5 m/s is dosing alum at 23 mg/litre. No other chemicals are being added. The raw water suspended solid concentration is 37 mg/l. The effluent suspended solid concentration is 12 mg/l. Sludge content is 1% and specific gravity of sludge is 3.01. What volume of sludge must be disposed of every day.
A wastewater treatment plant uses an activated sludge process to treat 0.2 m3/s of primary effluent. The concentration of the mixed liquor is 2,000 mg/L MLVSS (Mixed liquor volatile suspended solids), while the RAS (recycled activated sludge) concentration is 10,000 mg/L MLVSS. The substrate concentration in the primary effluent is 210 mg/L BOD5. The F/M ratio is 0.5 mg BOD5/(mg MLVSS-d) and the solids retention time is 8.5 d. What is the volume of the activated sludge tank? 2.What is the WAS (waste activated sludge) flowrate? 3.What is the flowrate of the secondary treated effluent? 4.What is the RAS (recycled activated sludge) flowrate? 5.What is the hydraulic residence time for the activated sludge tank?
A completely mixed activated sludge plant treats wastewater at a rate of 2,565 m³/d. The influent BOD is 280 mg/L, and the MLVSS in the aeration tank is 2,500 mg/L. The F/M ratio for the aeration tank is 0.35 kg BOD/kg MLVSS.d. Assuming 30% of BOD is removed in the primary tank, determine the organic loading rate in kg BOD/m³.d and the volume of the aeration tank in m³.
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A mixed liquor sample form an activated sludge plant was settled in a one-litre measuring cylinder for 30 minutes after which time, a volume of 350 m/ of sludge was recorded. When 50 m/ of the mixed liquor were filtered through a GFC paper for the determination of MLSS the gain in weight of the paper was 0.1375 g. Determine the SVI.
The quantity of sludge produced from an aeration tank is 2,453 kg/day. The volume of the aeration tank is 8,500 m3 and the yield is 0.55 mg VSS/mg BOD5. The water retention time is 1 day and the inlet BOD5 is 540 mg/L. Calculate the outlet BOD5 in the tank?
Q2-) The waste flow 18000 m³/day is treated by activated sludge process to reduce 97.5% of influent BODS proce concentration of 250 mg/L. The ratio of formed cell mass and substrate utilized mass are 0.4 and 0.8, respectively, MLVSS = 3500 mg/L, return sludge (Xr) = 8000 mg/L, decay growth rate = 0.05, and 8c = 10 days. Find the following: 1. Reactor volume and hydraulic retention time. 3. The daily amount of wasted sludge. 5. Food to microorganisms' ratio. 2. The volumetric organic loading 4. The recycle ratio, and treatment efficiency.
Coagulation aided sedimentation produces 135m³ of sludge per day. The solid content of sludge is 1% by weight and specific gravity of sludge solid is 2.7. If 20 my of suspended solids are removed from the raw water by the Al(OH)3 precipitate formed, and flow through the treatment plant is 40 MLD, then the amount of alum required per day in kg is
Q2-) The waste flow 18000 m'/day is treated by activated sludge process to reduce 97.5% of influent BOD, concentration of 250 mg/L. The ratio of formed cell mass and substrate utilized mass are 0.4 and 0.8, respectively, MLVSS = 3500 mg/L, return sludge (Xr) = 8000 mg/L, decay growth rate= 0.05, and 0 = 10 days. Find the following: 1. Reactor volume and hydraulic retention time. 3. The daily amount of wasted sludge. 5. Food to microorganisms' ratio. 2. The volumetric organic loading 4. The recycle ratio, and treatment efficiency.
A coagulation treatment plant with a flow of 0.5 m3/s is dosing alum at 20 mg/l. Concentration of suspended solid is 25 mg/l. The effluent suspended solid concentration is 12 mg/l. The sludge content is 1 % and specific gravity of sludge is 3 %. What volume of sludge must be disposed of each day?
After mixing with a waste discharge, the initial ultimate BOD of a river is 12 mg/L. The DO in the river after the wastewater and river have mixed is at saturation. The river temperature is 10°C. At 10°C, the deoxygenation rate constant is 0.3 day-1, and the reaeration rate constant is 0.4 day-1. Assuming DOsat is 11.33 mg/L @ 10°C and 10.15 mg/L @ 15°C, a. Determine the critical point at days and the critical DO mg/L. b. Assuming the river temperature rises to 15°C in summer so that both rate constants change, determine the critical point at days and the critical DO mg/L. 6.11 11.33 2.42 4.04 10.15 3.79 0.45 7.54 2.88 0.38 A city disposes of its treated wastes to a river on a continuous basis. The minimum flow in the river is 210 m³/s, and the discharge rate from the treatment plant is 12.5 m³/s. Assume that the maximum acceptable limit for a certain pollutant is 1 mg/L in the downstream river, and the background concentration of this pollutant upstream is 0.4 mg/L. a. The maximum…
A completely mixed activated sludge process operating at equilibrium is designed to treat 300 MLD of waste water. The influent and effluent BOD are 200 mg/1 and 18 mg/1 respectively If the F M then the hydraulic retention time is A 0.125 day B 4.21 hours C 8.42 hours D 0.225 day = 0.3 and MLSS is 3800 mg/1,

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