5. An electrochemical cell is based on these two half-reactions: Oxidation: Cu(s) → Cu2+(aq, 0.010 M) + 2 e- Reduction: MnO4 -(ag, 2.0 M) + 4 H+(aq, 1.0 M) + 3 e- MnO2(s) + 2 H2O(l) Calculate the cell potential.

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter18: Electrochemistry
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Problem 18.67QE
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5. An electrochemical cell is based on these two half-reactions:
Oxidation: Cu(s) → Cu2+(aq, 0.010 M) + 2 e-
Reduction: MnO4 -(ag, 2.0 M) + 4 H+(aq, 1.0 M) + 3 e- MnO2(s) + 2 H2O(l)
Calculate the cell potential.
Transcribed Image Text:5. An electrochemical cell is based on these two half-reactions: Oxidation: Cu(s) → Cu2+(aq, 0.010 M) + 2 e- Reduction: MnO4 -(ag, 2.0 M) + 4 H+(aq, 1.0 M) + 3 e- MnO2(s) + 2 H2O(l) Calculate the cell potential.
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