8-2. Data taken from a stress-strain test for a ceramic aregiven in the table. The curve is linear between the origin andthe first point. Plot the diagram, and determine the modulusof elasticity and the modulus of resilience.o (MPa) e (mm/mm)232.4318.50.00060.0010345.80.00140.0018360.5373.80.0022

Given stress-strain is giving in the table,

Answered: 8-2. Data taken from a stress-strain…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Part B Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. Determine the modulus of elasticity. VO AEO vec ? E = ksi Submit Request Answer Figure 1 of 1 Part C σ (ksi) e (in./in.) Determine the modulus of resilience. ΑΣφ ? vec 33.2 0.0006 45.5 0.0010 in-lb Up = in 49.4 0.0014 51.5 0.0018 Submit Request Answer 53.4 0.0022
Review Data taken from a stress-strain test for a ceramic are No elements selected o(ksi) given in the table. The curve is linear between the origin and the first point. 50 40 30 Figure 1 of 1 20 10 σ (ksi) e (in./in.) ex 10-*(in./in.) 0.5 1.0 1.5 2.0 25 33.2 0.0006 45.5 0.0010 Press (ENTER to select this element. Press (ESc to return to the main menu. Press (CTRL+Q) to quit the application. 49.4 0.0014 51.5 0.0018 53.4 0.0022
Stress Strain Diagram The Data shown in the table have been obtained from a tensile test conducted on a high-strength steel. The test specimen had a diameter of 0.505 inch and a gage length of 2.00 inch. Using software. plot the Stress-Strain Diagram for this steel and determine its: A= TTdT(050s A %3D 1. Proportional Limit, 2. Modulus of Elasticity, 3. Yield Strength (SY) at 0.2% Offset, 4. Ultimate Strength (Su), 5. Percent Elongation in 2.00 inch, 6. Percent Reduction in Area, 7. Present the results (for Steps 1-6) in a highly organized table. e Altac ie sheet (as problelle 4 A = 0.2.002 BEOINNING of the effort Elongation (in) Elongation (In) Load Load #: #3 (Ib) (Ib) 1 0.0170 15 12,300 0.0004 1,500 16 12,200 0.0200 0.0010 3. 3,100 17 12,000 0.0275 0.0016 4,700 18 13,000 0.0335 5. 6,300 0.0022 19 15,000 0.0400 0.0026 6. 8,000 20 16,200 0.055 0.0032 9,500 21 17,500 0.0680 0.0035 8. 11,000 22 18,800 0.1080 0.0041 11,800 23 19,600 0.1515 0.0051 24 20,100 0.2010 10 12,300 0.0071 25…
Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. Figure σ (ksi) 0 33.2 45.5 49.4 51.5 53.4 € (in./in.) 0 0.0006 0.0010 0.0014 0.0018 0.0022 1 of 1 Part B Determine the modulus of elasticity. E = ksi Submit Part C Determine the modulus of resilience. Ur= in-lb in³ Submit Request Answer Provide Feedback Request Answer
Determine the elastic modulus and the yield strength for the material having the stress-strain curve shown. Use the 0.2% offset method. 1600 1400 1200 E 1000 800 600 400 200 0.5 1 1.5 2 Strain, percent Elastic modulus: (Express your answer in whole numbers.) E = ksi Yield strength: (Express your answer using three significant figures.) Sy = ksi Stress, psi
The following data was obtained as a result of tensile testing of a standard 0.505 inch diameter test specimen of magnesium. After fracture, the gage length is 2.245 inch and the diameter is 0.466 inch. a). Calculate the engineering stress and strain values to fill in the blank boxes and plot the data. Load(lb) Gage Length (in) Stress (kpsi) Strain 0 2 1000 2.00154 2000 2.00308 3000 2.00462 4000 2.00615 5000 2.00769 5500 2.014 6000 2.05 6200 (max) 2.13 6000 (fracture) 2.255 b). Calculate the modulus of elasticity c). If another identical sample of the same material is pulled only to 6000 pounds and is unloaded from there, determine the gage length of the sample after unloading.
The shear stress-shear strain diagram for a material is shown. The bolt used to hold the lap joint is made of this material and has a diameter of 0.35 in. The material has a Poisson's Ratio of 0.2. T (ksi) F T1 G = Values for the figure are given in the following table. Note the figure may not be to scale. Variable T1 Y1 Value 40 ksi 0.003 rad 71 -7 (rad) a. Determine the Shear Modulus of the allow, G. b. Determine the Elastic Modulus of the allow, E. c. Determine the force required to cause the material to yield, F. Round your final answers to 3 significant digits/figures. ksi
A tensile test specimen of stainless steel alloy having a diameter of 0.495 in. and a gage length of 2.00 in. was tested to fracture. Stress and strain data obtained during the test are shown. Determine the proportional limit. Stress (ksi) 40 30- 20 10- 0- 0.0 0.0 Upper scale 0.020 0.002 22 ksi O 15 ksi E 19 ksi O 10 ksi 13 ksi Lower scale- 0.040 0.060 0.080 0.100 0.004 0.006 0.008 0.010 Strain (in./in.) 0.120 0.012
Determine the tensile yield strength (0.2% offset) and the maximum strength of a metal alloy having the following tensile stress-strain diagram. 600 500 400 500 300 400 300E 200 3200 100 100E 0.000 0.002 0.004 0.006 Strain ol 0.00 0.16 0.20 0.08 Strain 0.04 0.12 Select one: O The tensile yield strength Sy = 290 Mpa and the maximum strength Smax = 500 Mpa. O The tensile yield strength Sy = 170 Mpa and the maximum strength Smax = 400 Mca. G The tensile yield strength Sy = 200 Mpa and the maximum strength Smax = 500 Moa. O Tne tensile yield strength Sy = 390 Mpa and the maximum strength Smax= 500 Mpa. The tensile yed strength Sy = 150 Mpa and the maximum strength Smax = 250 Mpa. Stress (MPa) Stress (MPa)
Determine the tensile yield strength (0.2% offset) and the maximum strength of a metal alloy having the following tensile stress-strain diagram. Select one: The tensile yield strength Sy = 100 Mpa and the maximum strength Smax = 250 Mpa. The tensile yield strength Sy = 170 Mpa and the maximum strength Smax = 250 Mpa. The tensile yield strength Sy = 150 Mpa and the maximum strength Smax = 200 Mpa. The tensile yield strength Sy = 240 Mpa and the maximum strength Smax = 250 Mpa. The tensile yield strength Sy = 80 Mpa and the maximum strength Smax = 250 Mpa.
2) The stress-strain diagram for an alloy specimen having an original diameter of 0.5 in. and a gage length of 2 in. is shown in the figure below. TENSILE STRESS (MPA) 450 400 350 300 250 200 150 100 50 Part A 0 0 STRESS VS. STRAIN 0.002 0.004 STRAIN 0.006 Determine the modulus of resilience. Show units. Part B Determine the modulus of elasticity of the material. Part C Estimate the Yield Strength of the material. 0.008 0.01
The stress-strain diagram for a steel alloy having an original diameter of 0.7 in. and a gage length of 4 in. is shown in (Eigure 1). The specimen is loaded until it is stressed to 70 ksi. Figure (ksi) 80 70 60 50 40 30 20 10 0 0 0.04 0.05 0.12 016 020 024 028 0 000050001 DEBES 000200 Determine the approximate amount of elastic recovery. Express your answer in inches to three significant figures. IVE ΑΣΦ. It Ivec Amount of Elastic recovery => Submit Part B Determine the increase in the gage length after it is unloaded. Express your answer in inches to three significant figures. VAX Request Answer Permanent elongation=

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