A 1-2 line was divided into sections on sloping terrain using a 30-meter tape, and thesubsequent readings were documented:SlopeDifference indistance (m) elevation (m)30.001.5830.000.9518.920.9011.460.5630.003.018.230.69Determine the total correction due to slope in meters using approximate solution.Express answer into three decimal places.

Answered: Image /qna-images/answer/10485df8-1ccc-480d-87ef-2f5b3d1384ab.jpg

Answered: A 1-2 line was divided into sections on…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The field level book readings from a fly level are as follows: Staff station BM-1 A B C BM-2 RL 100.000 X 104.150 4.220 106.650 3.990 108.000 BS 3.635 X FS 2.375 1.030 X X Remarks Find out the missing values marked (x) and perform the arithmetic check(s).
Reduce the following set of differential leveling notes and perform the arithmetic check. Station BM 130 TP 1 TP 2 TP 3 BM K110 TP 4 BM 132 BS (m) 0.702 0.970 0.559 1.744 1.973 1.927 HI (m) FS (m) 1.111 0.679 2.780 1.668 1.788 0.888 Elevation (m) 168.657 1. Determine the order of accuracy. 2. Adjust the elevation of BM K110. The length of the evel run was 780 m, with setups equally spaced. The elevation of BM 132 is known to be 167.629 m.
Reduce the following set of differential leveling notes and perform the arithmetic check. Station BM 130 TP 1 TP 2 TP 3 BM K110 TP 4 BM 132 BS (m) 0.702 0.970 0.559 1.744 1.973 1.927 HI (m) FS (m) 1.111 0.679 2.780 1.668 1.788 0.888 Elevation (m) 168.657
4-) Complete the benchmark-leveling field notes by computing and recording the HI and elevation for each TP and Benchmark. Do the arithmetic check. STATION BS HI ES ELEVATION STATION BS HI FS ELEVATION BM1 2.367 200.00 BM1 3.784 150.00 1 0.345 1.277 1 1.451 0.278 2 1.128 3.785 2 0.555 2.123 3 0.978 0.426 3 2.354 0.754 4 2.127 0.785 0.750 1.075 BM2 3.945 BM2 2.102 BS FS BS FS
Surveying Question: A differential leveling circuit starts at benchmark Concrete Benchmark (Elevation=232.051m) goes out to an unknown benchmark and then continues to a known control point (Elevation=227.975m). Two turning points are used with the measurements included in the attached table. Determine the elevation of the unknown benchmark Determine the order and class of the survey. For First order Class 1: Allowable Error= +/- 4(K)1/2 Range of Constant= m less than/equal to 4 For First Order Class 2: Allowable error= +/- 5(K)1/2 Range of constant= m greater than/equal to 4, and m less than equal to 5 (between 4 and 5) For Second Order Class 1: Allowable error = +/- 6(K)1/2 Range of Constant = m greater than/equal to 5, and m less than equal to 6 (between 5 and 6) For Second Order Class 2: Allowable error = +/- 8(K)1/2 Range of Constant = m greater than/equal to 6, and m less than equal to 8 (between 6 and 8) For Third Order, Any Class: Allowable Error = +/-12(K)1/2 Range…
Given the three-wire leveling note below, find the elevation of BM2 and perform the customary arithmetic check. Sta BM1 TP1 TP2 TP3 BM2 Hair Rgds 1.152 0.935 0.718 1.713 1.440 1.167 2.784 2.350 1.916 0.913 0.730 0.547 Backsight Mean Rgds (#1) (#4) (#7) S (#2) HI (#3) Hair Rgds Foresight Mean Rgds S 1.177 0.899 0.621 1.905 1.537 1.169 1.450 1.177 0.904 2.210 1.714 (#8) (#9) 1.218 (#5) Elev 450.545 (#6) (# 10)
Starting from point A of reduced level 200, the levels were taken to another point B. The reduced level of point B was found to be 198.295. In order to check the leveling work flying levels were taken from point B to point A and the following readings were obtained. Find the error of closure on point A. * Point B.S F.S А 1.015 2.125 3.005 3.005 3.755 2.975 2.525 1.625 2.435 3.015 1.015 1.075 1.535 2.725 2.015 B 1.935
with the given table below, find the following:- Linear Error of Closure- Relative Error of Closure- BSE Bearing Distance Lat Dep cLat cDep AdjLat AdjDep AB S 68 5 35 W 472.68 -176.36 -438.55 45.67633474 45.67926201 -130.68 -392.87 BC N 19 46 0 W 216.3 73.09 -203.40 20.88522093 20.8865594 93.98 -182.51 CD N 45 55 20 E 276.52 192.35 198.65 26.72086842 26.72258088 219.08 225.37 DA S 54 59 15 E 382.24 -219.31 313.06 36.93687525 36.93924243 -182.38 350.00 1347.57 ∈latitude=el=-130.22 ∈departure=ed=-130.23 130.2192993 130.2276447 0.00 0.00
Problem #1: Leveling in a loop Leveling is performed to determine elevations on the ground and heights of instruments at each setup. Data is provided in the table below. FS Station J TP1 TP2 TP3 K TP4 TP5 J BS A 5.18 2.91 7.39 E 4.22 5.32 HI 319.83 322.87 322.1 D 322.93 F 320.33 315.36 Determine the following: 2.14 с 6.04 4.27 5.96 6.18 4.97 ELEV 315.76 B 319.19 316.06 319.18 316.97 315.01 G a. The unknown values A, B, C, D, E, F, and G in the table. b. Perform a math check. c. If the starting and ending elevations at point J are not the same, adjust the elevations.
a) 0.700 The following readings were taken in sequence during a leveling job: Readings (m) 1.250 1.285 1.125 0.810 1.555 -1.400 1.235 0.665 1.905 Remarks BMI R.L. = 101.335 Peg A Peg B 2 Change Point CP2 Change Point CP2 BM2 R.L=103.879 -1.400 Change Point CP1 Change Point CP1 CGS 1905 Inverted staff reading taken to the underside of a bridge Peg C Prepare a standard form of booking for these readings and reduce them using the rise fall method applying all the necessary arithmetic checks and adjust the final Reduced Levels.
46 K/s ۱۸ من ۱۸ Q.3 A level circuit is shown in figure. The survey, needed for local engineering project, commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 Elevation(m) 119.010(fixed) 35 36 37 38 39 35 123.342 118.206 118.451 120.491 118.933 BM 38 0.9 kg BM 35 DUM 37 08 km 06 km BM 38 سلوان 2 8:11p äc lul 21.03.06
A line of levels was run from station A to station B. The leveling was continued to a BM of elevation 40 m. The stadia readings were obtained as follows. What is the elevation of station A? What is the elevation of station B? BS HI FS IFS ELEV REMARKS 1.195 A 0.445 2.370 2.150 0.995 0.720 B 1.465 0.260 2.630 0.905 1.305 40.00 BM Choices: 37.655 m 37.523 m 37,950 m 38.201 m

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