A cross in plants is done between the parents CCDD and ccdd to create a dihybrid F1 plant. This F1 plant was subsequently test crossed to a ccdd plant and you find the the progeny as follows:40% CD40% cd10% Cd10% cD If you did a similar experiment in which the parents were changed to ccDD and CCdd, what percentage of the test cross progeny would have the cd phenotype? 40% 80% 10% 20%

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Description: A cross in plants is done between the parents CCDD and ccdd to create a dihybrid F1 plant. This F1 plant was subsequently test crossed to a ccdd plant and you find the the progeny as follows:40% CD40% cd10% Cd10% cD If you did a similar experiment i

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A cross in plants is done between the parents CCDD and ccdd to create a dihybrid F1 plant. This F1 plant was subsequently test crossed to a ccdd plant and you find the the progeny as follows: 40% CD 40% cd 10% Cd 10% cD

A cross in plants is done between the parents CCDD and ccdd to create a dihybrid F1 plant. This F1 plant was subsequently test crossed to a ccdd plant and you find the the progeny as follows: 40% CD 40% cd 10% Cd 10% cD

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...

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You make a test cross between an F1 plant that is heterozygous for two dominant resistance genes (R1 and R2) and a line that is homozygous recessive at both loci, and inoculate the progeny with a pathogen race that is avirulent on both R1 and R2 (i.e., it carries avirulence genes Avr1 and Avr2).You get 50 susceptible progeny out of 200 test cross progeny. (a) What is the linkage phase for these two genes? (b) What is the recombination distance?
In three points mapping the F1 parent has the A+B+C+genotype, what is the genotype of the other F1 parent?
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In pineapples, leaves may be spiny, spiny-tipped or piping. Pineapples of different phenotypes were used in the following crosses: Pl phenotype piping X spiny P1 genotype Fl phenotype 100% piping F1 genotype Crossing the Fls produced: F2 phenotypes F2 genotypes ww gm 95 piping 25 spiny tipped 8 spiny Using the letters A and B, give the COMPLETE genotypes of ALL the individuals. SOLUTION Get the total of the F2 generation
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