A footing 2.50 m x 2.50 m is located at a depth of 1.5 m in sand. The shear strength parameters to be used in design are c' = 0 and o' = 38°. What is the net ultimate bearing capacity of footing if the water table is at 3 m below foundation level? The unit weight of sand is 18 kN/m3 and FOS = 3 For O' = 38°, N, = 67 and Ng = 49

A footing 2.50 m x 2.50 m is located at a depth of 1.5 m in sand. The shear strength parameters to be used in design are c' = 0 and o' = 38°. What is the net ultimate bearing capacity of footing if the water table is at 3 m below foundation level? The unit weight of sand is 18 kN/m3 and FOS = 3 For O' = 38°, N, = 67 and Ng = 49

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter17: Settlement Of Shallow Foundations

Section: Chapter Questions

Problem 17.12P

See similar textbooks

Similar questions

A footing 2.25 x 2.25 m is located at a depth of 1.5 m in a sand, the shear strength parameters to be used in design being c' = 0 and ϕ' = 38˚. Determine the ultimate bearing capacity: (a) if the water table is well below foundation level and (b) if the water table is at the surface. The unit weight of the sand above the water table is 18 kN/m^3; the saturated unit weight is 20 kN/m^3. Note: Use the equations to solve for Nc, Nq and Nγ.
A rectangular footing has dimensions shown and is acted upon by a dead load of 668.00 kN and a live load of 551.00 kN. The column dimension is 282x572 mm where the shorter dimension is parallel to B. The thickness of the footing is 564mm. f'c=28 MPa and fy=420 MPa for diameter 20mm bars. A=3.3m and B=5.7m Calculate the ratio of the Ultimate Shear Force to Shear Capacity in one- way shear. Consider critical case only. Answer is 0.6175 (Complete Solution)A
A rectangular footing has dimensions shown and is acted upon by a dead load of 570.00 kN and a live load of 621.00 kN. The column dimension is 366x576 mm where the shorter dimension is parallel to B. The thickness of the footing is 476mm. f'c=28 MPa and fy=420 MPa for diameter 20mm bars. A=2.5m and B=4.5m Calculate the ratio of the Ultimate Shear Force to Shear Capacity in two- way shear. Answer is 0.9238 (Complete Solution)
A rectangular footing has dimensions shown and is acted upon by a dead load of 653 KN and a live load of 647 kN. The column dimension is 269x677 mm where the shorter dimension is parallel to B. The thickness of the footing is 442mm. f'c=28 MPa and fy=420 MPa for diameter 20mm bars. A=2.9m and B=4.8m Calculate the ratio of the Ultimate Shear Force to Shear Capacity in one-way shear. Consider critical case only.
A strip footing 2.5 m wide is to be constructed at a depth of 3m below ground level. The shear strength parameters to be used in design being c|= 65kN/m2 and ø| = 34°. The unit weight of the soil above water table is 18kN/m3 , and below the water table the saturated unit weight is 20kN/m3. a. If the water table is well below foundation level b. If the water table is at the surface.
A rectangular footing has dimensions shown and is acted upon by a dead load of 1200 kN and a live load of 1600 kN. The column dimensions is 300x600 where the shorter dimension is parallel to B. The thickness of the footing is 500mm. f'c = 28 MPa and fy = 420 MPa for diameter 20mm bars. A = 2.4m and B = 4.2m Calculate the Following: A.) Critical Ultimate Shear Strength and Shear Force of the footing for beam shear action, kNB.) Critical wide beam nominal shear stress, MPaC.) Ultimate Shear Strength of the footing in punching shear action, kN Please answer it ASAP and correctly for upvotes.
A rectangular footing has a dimensions shown and is acted upon by a dead load of 722 kN and a live load of 620 kN. The column dimension is 326 x 662 mm where he shorter dimension is parallel to B The thickness of the footing is 408mm. f'c=28 MPa and fy=420 MPa for diameter 20mm bars. A=3.1m and B=5.1m
A square footing shown has the following details: Unit weight of soil = 15.28 kN/m3 Saturated unit weight of soil = 19.92 kN/m3 cohesion = 21.44 kPa %3D friction angle = 24 degrees %3D B = 2 meter Df = 2.45 meter P = 861 kN e/B = 0.12 --> one way eccentricity Calculate for the net allowable bearing capacity using FOS = 2.8. Use Meyerhof General Bearing Capacity Formula. D, B B Water table
5A strip footing was constructed on a pure sand which is 1.5 m wide with its base at a depth of 1 m. Using Terzaghi's method, the ultimate bearing capacity of strip footing will be [Take Y₁ = 16 kN/m³, N = 75, Assume general shear failure] 1 (a) 1876 kN/m² (b) 1860 kN/m² (d) 1792 kN/m² (c) 1788 kN/m²
A rectangular footing of breadth size 3 m and length 5 m is designed on CLAY at a depth of 1.5 m below the ground level to support a vertical load of 1200 kN. The unit weight of the soil is 19 kN/m³ and shear strength parameters are cu 65 kN/m² and θ =0°. Calculate factor of safety and take the appropriate bearing capacity coefficient Nc, Nq, and Nr, as 5.7, 1.0 and 0 respectively.
A strip footing is to be designed to support a dead load of 500 kN/m and an imposed load of 300 kN/m at a depth of 0.7 m in a gravelly sand. Characteristic values of the shear strength parameters are c' = 0 and ϕ' =40˚. (a) Determine the required width of the footing if a factor of safety of 3.0 and assuming that the water table may rise to foundation level. (b) Would a foundation of that width satisfy the bearing resistance limit state? The unit weight of the sand above the water table is 17 kN/m3 and below the water table the saturated unit weight is 20 kN/m3.
3. A square footing that carries an axial load of 150000kg has its bottom resting on a ground water table at a depth of 2.5m from the ground surface. Take PDRY = 1860kg/m3 and PSAT = 1950kg/m3, c = 1600kg/m2, ø = 30degrees. Use the approximate formulas for the determination of the bearing capacity factors. a.Compute the required width of the footing using a factor of safety of 2. b.Compute the ultimate bearing capacity of the soil. c.Compute the net factor of safety. d.Compute the net soil pressure.