Alert for not submit AI generated answer. I need unique and correct answer. Don't try to copy from anywhere. Do not give answer in image formet and hand writing A nanoparticle containing 6 atoms can be modeled approximately as an Einstein solid of 18 independent oscillators. The evenly spacedenergy levels of each oscillator are 4 x 10-21 J apart. Use k = 1.4 x 10-23 J/K.Part 1(a) When the nanoparticle's energy is in the range 5 x 4x 10-21 J to 6 x 4x 10-21 J, what is the approximate temperature? (In orderto keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.)iKPart 2Submit Answer(b) When the nanoparticle's energy is in the range 8 x 4x 10-21 J to 9 x 4x 10-21 J, what is the approximate temperature? (In orderto keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.)iKPart 3Submit Answer(c) When the nanoparticle's energy is in the range 5 x 4x 10-21 J to 9 x 4x 10-21 J, what is the approximate heat capacity per atom?J/KNote that between parts (a) and (b) the average energy increased from "5.5 quanta" to "8.5 quanta". As a check, compare yourresult with the high temperature limit of 3k, where k = 1.4 x 10'23 J/K.

Given,The energy, The number of independent oscillator, The entropy, a. The number of quanta,The…

A nanoparticle containing 6 atoms can be modeled approximately as an Einstein solid of 18 independent oscillators. The evenly spaced energy levels of each oscillator are 4 x 10-21 J apart. Use k = 1.4×10-23 J/K. Part 1 (a) When the nanoparticle's energy is in the range 5 x 4x 10-21 J to 6x4x 10-21 J, what is the approximate temperature? (In order to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.) i к Part 2 Submit Answer (b) When the nanoparticle's energy is in the range 8 x 4x 10-21 J to 9 x 4x 10-21 J, what is the approximate temperature? (In order to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.) i к Part 3 Submit Answer (c) When the nanoparticle's energy is in the range 5x4x 10-21 J to 9x 4x 10-21 J, what is the approximate heat capacity per atom? J/K Note that between parts (a) and (b) the average energy increased from "5.5 quanta" to "8.5 quanta". As a check, compare your result with the high temperature limit of 3k, where k 1.4 x 1023 J/K -

A nanoparticle containing 6 atoms can be modeled approximately as an Einstein solid of 18 independent oscillators. The evenly spaced energy levels of each oscillator are 4 x 10-21 J apart. Use k = 1.4×10-23 J/K. Part 1 (a) When the nanoparticle's energy is in the range 5 x 4x 10-21 J to 6x4x 10-21 J, what is the approximate temperature? (In order to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.) i к Part 2 Submit Answer (b) When the nanoparticle's energy is in the range 8 x 4x 10-21 J to 9 x 4x 10-21 J, what is the approximate temperature? (In order to keep precision for calculating the heat capacity, give the result to the nearest tenth of a degree.) i к Part 3 Submit Answer (c) When the nanoparticle's energy is in the range 5x4x 10-21 J to 9x 4x 10-21 J, what is the approximate heat capacity per atom? J/K Note that between parts (a) and (b) the average energy increased from "5.5 quanta" to "8.5 quanta". As a check, compare your result with the high temperature limit of 3k, where k 1.4 x 1023 J/K -