A rock with mass 2 kg is thrown upwards with aninitial speed of 19 m/s. Air resistance isproportional to speed, with constant of1kg/s.9proportionality kAssuming the stone is launched at time t = 0,find an expression for the velocity of the stone asa function of time.v(t)t===When does the stone reach its maximum height?17119 + 9.81t1-t9XXS

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Description: A rock with mass 2 kg is thrown upwards with aninitial speed of 19 m/s. Air resistance isproportional to speed, with constant of1kg/s.9proportionality kAssuming the stone is launched at time t = 0,find an expression for the velocity of the stone asa

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A rock with mass 2 kg is thrown upwards with an initial speed of 19 m/s. Air resistance is to speed, with constant of proportional 1 proportionality kg/s. 9 v(t) Assuming the stone is launched at time t = 0, find an expression for the velocity of the stone as a function of time. t = - k = 171 When does the stone reach its maximum height? 19 + 9.81t 1− t 9 X X S

A rock with mass 2 kg is thrown upwards with an initial speed of 19 m/s. Air resistance is to speed, with constant of proportional 1 proportionality kg/s. 9 v(t) Assuming the stone is launched at time t = 0, find an expression for the velocity of the stone as a function of time. t = - k = 171 When does the stone reach its maximum height? 19 + 9.81t 1− t 9 X X S

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter3: Motion Along A Straight Line

Section: Chapter Questions

Problem 112CP: In a 100-rn race, the winner is timed at 11.2 s. The second-place finisher’s time Is 11.6 s. How far...

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