A solution of phosphoric acid (HPO4) with a known concentration of 0.250 M HsPO4 is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 72.0 mL HPO4 according to the following balanced chemical equation: H₂PO4 + 3 NaOH → NasPO4 + - 3 H₂O

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10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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JKU Portal D2 D2L ii Handshake
<
STARTING AMOUNT
X
Ch. 1 Introduction -...
4
Aktiv Chemistry
72.0
ADD FACTOR
43.2
Connect-Bio Google Docs O Quizlet
A solution of phosphoric acid (H.PO4) with a known concentration of 0.250 M H3PO4
is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to
reach the third equivalence point with a starting volume of 72.0 mL H3PO4
according to the following balanced chemical equation:
0.0675
mL NaOH
H₂PO4 +
0.800
g NaOH
1
Question 19 of 23
3 NaOH NasPO4 +
6.75 x 104
LH₂PO4
2
mol H3PO4
→
H2023 Elantra hybrid
0.250
1000
g H₂PO4
ANSWER
mL H₂PO4
3 H₂O
0.001
67.5
M H3PO4
mol NaOH
2022 Subaru WRX
RESET
M NaOH
S
7.50
22.5
LNaOH
3
2023 Kia K5 | Mid-S...
Transcribed Image Text:JKU Portal D2 D2L ii Handshake < STARTING AMOUNT X Ch. 1 Introduction -... 4 Aktiv Chemistry 72.0 ADD FACTOR 43.2 Connect-Bio Google Docs O Quizlet A solution of phosphoric acid (H.PO4) with a known concentration of 0.250 M H3PO4 is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 72.0 mL H3PO4 according to the following balanced chemical equation: 0.0675 mL NaOH H₂PO4 + 0.800 g NaOH 1 Question 19 of 23 3 NaOH NasPO4 + 6.75 x 104 LH₂PO4 2 mol H3PO4 → H2023 Elantra hybrid 0.250 1000 g H₂PO4 ANSWER mL H₂PO4 3 H₂O 0.001 67.5 M H3PO4 mol NaOH 2022 Subaru WRX RESET M NaOH S 7.50 22.5 LNaOH 3 2023 Kia K5 | Mid-S...
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