Amplifier's Frequency Response Vcc=20V R1 = 40 kohm R2 = 10 kohm Rc = 4 kohm RE=2 kohm Rs = 1 kohm RL = 2.2 kohm Cs = 10 uF Cc = 1 uF CE = 20 uF Cbc = 4 pF Cbe = 36 pF Cce 1 pF Cwi= 6 pF Cwo = 8 pF Beta = 100 Rs +I 2 V₁ + C. d. R₁ Vcc R₂ Cw₁ Cbc RC Сbe RE Cc Cce Calculate the cutoff frequency due to CE. a. 222 Hz b. 327 Hz 489 Hz 577 Hz RL Cwo 111 CE ●●● 4

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AMPLIFIER'S FREQUENCY RESPONSE 5

Amplifier's Frequency Response
Vcc=20V
R1 = 40 kohm
R2 = 10 kohm
Rc = 4 kohm
RE=2 kohm
Rs = 1 kohm
RL = 2.2 kohm
Cs = 10 uF
Cc = 1 uF
CE = 20 uF
Cbc = 4 pF
Cbe = 36 pF
Cce 1 pF
Cwi= 6 pF
Cwo = 8 pF
Beta = 100
Rs
+I
2
V₁
+
C.
d.
R₁
Vcc
R₂ Cw₁
Cbc
RC
Сbe
RE
Cc
Cce
Calculate the cutoff frequency due to CE.
a.
222 Hz
b.
327 Hz
489 Hz
577 Hz
RL
Cwo
111
CE
●●●
4
Transcribed Image Text:Amplifier's Frequency Response Vcc=20V R1 = 40 kohm R2 = 10 kohm Rc = 4 kohm RE=2 kohm Rs = 1 kohm RL = 2.2 kohm Cs = 10 uF Cc = 1 uF CE = 20 uF Cbc = 4 pF Cbe = 36 pF Cce 1 pF Cwi= 6 pF Cwo = 8 pF Beta = 100 Rs +I 2 V₁ + C. d. R₁ Vcc R₂ Cw₁ Cbc RC Сbe RE Cc Cce Calculate the cutoff frequency due to CE. a. 222 Hz b. 327 Hz 489 Hz 577 Hz RL Cwo 111 CE ●●● 4
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