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- Q4) Determine the maximum service load than can be applied if the live load to DL ratio is 2. All structural steel is A36and the weld is a % inch fillet weld with E70 electrodes. Section is not double angle. Check if this weld size, length meets the code requirements? 2L5 x 3½ x %6 LLBB 5"20. determine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksit) what is the weld capacity perpedicular to the beam of the flange connection in kips? (2 decimal places)i) what is the weld capacity of the shear connection in kips? (2 decimal places)A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi
- (25 Marks) 05: A plate 4 x 6 of A36 steel is used as a tension member to carry a service dead load of 6 kips and a service live load of 18 kips. It is to be attached to a 3/8" gusset plate. Using 3/16" fillet weld, using E70XX electrodes. Is the strength of the weld adequate? Note: 00 Weld PL ¼x6 A36 steelThe connection of the drawbar and tie plate combination given below will be made by welding with two UPE200 profiles given end to end and a tie plate with a thickness of t=10 mm. Determine the design of the welded joint, namely the weld thicknesses and lengths. t=10 t= 8 a, 4 a, 4 UPE 120[ ] a1, l1 120 P= 500 kN a,, l, 60 az, l2 a,, Sectional View Side View Dimensions: mmIf 100 mm leg of ISA 100 65 8mm angle is connected to the gusset plate as shown below with total weld length(Lw) of 290 mm. Calculate Lw1 and Lw2. Use steel table Lwl ISA 100 65 8 mm Lw2
- Design the size and length of Fillet weld for the lap joint shown below, Use SMAW E70XX process, plates are A-36 steel? 90k LL 40k DL R-X7 5" Gusset P 8 90k LL 40k DLDetermine the capacity of the details shown below. A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi i) what is the weld capacity of the shear connection in kips? (2 decimal places)Problem 2: What is the U value for these cases? 1. Plate connected using bolts (fasteners) only. 2. Plate using transverse welds only 3. 3/4 in thick plate using longitudinal welds only where the length of the weld (L=10 in) and L = 1.25 W where W is the width of the plate. 4. Single angle where both legs are bolted to the support. 5. Single angle L8x8x1 with longitudinal welds (L = 9 in) on one leg 6. Channel C10x20 connected using one bolt only in the web 7. Single angle connected on one leg using transverse and longitudinal welds.
- Calculate the maximum shear force in the welds and the required weld size in the given figure. Where P= 50kN X=60mm, Y=150mm, Z=100mm What is the maximum force on the weld in kN/mm? (2 decimal places) What is the required weld size considering E70xx fillet weld in mm? (rounded value)WT12 x 38 Longitudinal welds Given: Properties of WT12 x 38: A, = 11.2 in? y = 3.0 in. b = 8.99in. Use A992 Steel: F, = 50 ksi F = 65 ksi LL = 3 DL %3D %3D tw = centroidal distance bf A. Governing Ultimate Tensile Capacity based on Yielding of gross section Round your answer to 0 decimal places.The connection shows a PL10X200 loaded in tension and welded to a gusset plate 10mm thick. Calculate the following, assuming A992 steel is used. Use U =0.85. The weld thickness is ómm and the electrode is E70 (485MPA). PL 10 X 200 350mm What is the allowable weld connection strength (kN)?