Consider a byte-addressable computer with a 16-bit main memory address and 32 blocks of cache memory that are both accessible. After figuring out the offset field size using the assumption that each block includes 8 bytes, display your findings.
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- Suppose we have a byte-addressable computer using fully associative mapping with 16-bit main memory addresses and 32 blocks of cache. Supposed also that each block contains 16 bytes. The size of the offset field is 19 bits and the size of the block field is 0.625 bytes.Suppose we have a byte-addressable computer using fully associative mapping with 16-bit main memory addresses and 32 blocks of cache. If each block contains 16 bytes: (a) Determine the size of the offset field. (b) Determine the size of the tag field.Suppose a byte-addressable computer using set-associative cache has 216 bytes of main memory and a cache of 32 blocks, and each cache block contains 8 bytes.Q.) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, set, and offset fields?
- Suppose a computer using fully associative cache has 224 words of main memory and a cache of 512 blocks, where each cache block contains 16 words. How many blocks of main memory are there? What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag and offset fields? To which cache block will the memory reference 17042416 map?Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main memory addresses and 32 bits, the blocks of cache. Suppose also that each block contains 8 bytes. The size of the block offset field is bits, and the size of the tag field is bits. size of the set field isSuppose a computer using set associative cache has 216 words of main memory and a cache of 128 blocks, and each cache block contains 8 words. If this cache is 2-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields?
- Question 18 Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main memory addresses and 32 blocks of cache. Suppose also that each block contains 8 bytes. The size of the block offset field is bits, the bits. size of the set field is bits, and the size of the tag hield isIf we had a computer that can only address data in bytes, but it has fully associative mapping, 16-bit main memory addresses, and 32-bit cache memory blocks. If each block is 16 bytes in size, then...(a) Count the number of bytes in the offset field.The tag field's size in pixels must be calculated (b).Suppose you have a byte-addressable computer using fully associative mapping with 16-bit main memory addresses and 32 blocks of cache. If each block contains 16 bytes, determine the size of the tag field, and show how you arrived at the result.
- Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a cache of 128 blocks, where each block contains 64 bytes.Q.) What is the format of a memory address as seen by cache; that is, what are the sizes of the tag and offset fields?Consider a byte-addressable computer with 32-bit addresses, a cache capable of storing a total of 64K bytes of data, and cache blocks of size 128 bytes. If the computer uses direct mapping, the format of the memory address is as follows: bits for the tag field, bits for the cache block number, and bits for the block offset.Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main memory addresses and 32 blocks of cache. If each block contains 8 bytes, determine the size of the offset field, and show your work.