• Draw the 2 anomeric ringstructures for D-glucose, usingCHOthe information in the straight-н-с -онНо -с —нchain structure provided. In yourН-с -онfigure, number each of the CН-с -он1.ČH,OHatoms, and show the position ofevery OH group.

Glucose is a monosaccharide. It is aldohexose. It has six carbon atoms and a functional group…

Answered: • Draw the 2 anomeric ring structures…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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The anomer of a-D-glucopyranose is CH:OH он ÓH CH2OH он он он он CH,OH он он он он CH,OH он OH он ÓH ÇH;OH он он он он
NAZO NHZ Ala-Cys-Glu -Tyr - Trp - Lys - Arg - His -Pro-G ly Glu pka 4.15 SH Tyr 10.10 Draw Charges Lys 10.67 Olt A3 12.10 +NH₂ Ntrm 2) Calculate net charge 3) write out I letter code 300 Ctim 3 juli of peptich (above) Ⓒ pH; 1,7,12
Consider the positively charged amino acid lysine Lys2+ 21 COOH I H&N-C-H I pH 14 12 10 8 6 4 2 0 CH₂ I CH₂ I CH₂ I CH₂ T NH₂+ 0 Nelson p85 2.18 = 2.18 PK₁ Lys+ COO™ I H₂N-C-H H₂N-C-H ī I -----) 8.95 Lysº 8.95 pK₂ pka carboxyl = 2.19 pkaamino = 9.67 pka sidechain = 4.25 COO™ I CH₂ I CH₂ I CH₂ I CH₂ I NH₂¹ 1.0 2.0 Equivalents of OH added- COO™ I H₂N-C-H I 10.79 1 10.79 pk Isoelectric point Lys CH₂2 I CH₂ I CH₂ I CH₂ T NH₂ 3.0 +H3N NH3+ T CH₂ T CH₂ CH₂ CH₂ -COO™ H Lysine (Lys, K) Physiological pH = 7.4 < pl → Amino acid is positively charged at physiological pH 1. Consider glutamate in its fully protonated form (e.g. in a pH = 1 solution) 1) Draw all the forms of glutamate at various pH 2) Calculate the pl of this amino acid 3) Sketch a titration curve showing pH as a function of added [OH-] and locate the predominant forms of histidine in the curve STEPS: 1. Find the H atoms that can be removed on the molecule 2. Associated a pka value to each removable H. 3. Draw the Aa structure at:…
Which of the following statements is true O Sphingomyelin posses phosphoryl serine in addition to two long hydrocarbon chains, one contributed by a fatty acid and the other by sphingosine OLipid compositions of membrane mono-layers are symmetrical O Unsaturated fatty acids have double bond(s) in the cis configuration In ABO blood typing, lack of glycosyltransferase and galactosyltransferase produces AB blood group
Identify the link between glucose units and name the polymer. (hint: the link is between two glucose units. Locate the anomer - a or B- and relate it to the polymer) но но Chain но но но но Chain O (A) a(1-4) link O (B) B(1-4) link O (C) Amylose Both (A) and (C) O Both (B) and (C)
. The following diagram shows the biosynthesis of B12 coenzymes, starting with the vitamin. DMB is dimethylbenzimidazole. (a) What one additional substrate or cofactor is required by enzyme B? (b) Genetic deficiency in animals of enzyme C would result in exces- sive urinary excretion of what compound?
The melanocyte-stimulating peptide hormone a-melanotropin has the following sequence:Ser–Tyr–Ser–Met–Glu–His–Phe–Arg–Trp–Gly–Lys–Pro–Val(a) Write the sequence using the one-letter abbreviations.(b) Calculate the molecular weight of a-melanotropin, using data inTable
1.Ala-Phe-Lys-Val-Val-Glu From the above polypeptide, what amino acid/s go/goes inside the cell after the following treatment: Chemotrypsin, thermolysin, then finally pepsin. What protein is left undigested? Write the primary structure of the undigested protein? 2.K-V-F-W-P-L-A-Y a.Chemotrypsin treatment b.Trypsin treatment c.Pepsin treatment d.Thermolysin treatment 3.Total acid hydrolysis of a pentapeptide complemented by total alkalinehydrolysis yields an equimolar mixture of 5 amino acids listed alphabetically, ala-cys,lys,phe,ser. N-terminal analysis with phenylisothiocyanate (PITC) generate PTH-ser. Trypsin digestion produces a tripeptide where N-terminal residue is cys and a dipeptide with ser as its N- terminal.Chemotrypsin digestion of the above tripeptide yields ala plus another dipeptide. A.What is the amino acid sequence of the tripeptide B.What is the amino acid sequence of the dipeptide derived from trypsin digestion? C.What is the primary structure of the original…
R HO OH OH H₂N CH3 protein asparagine side chain activated sugar Draw the product of the asparagine glycosylation reaction, assuming inversion of configuration of the anomeric carbon.
Draw the Fischer Projection, Haworth and Chair conformation for D-Glucose
First letter U C A UUU UU JUC UUA UUG CUU CUC CUA CUG AUU AUC AUA AUG GUU GUC GUA GUG ] Phenylalanine UCU (Phe) UCC UCA UCG Leucine (Leu) Leucine (Leu) Isoleucine (Ile) Methionine (Met) Valine (Val) CCU CCC CCA CCG b) lysine c) methionine d) tryptophan ACU ACC ACA ACG GCU GCC GCA GCG C Second letter Serine (Ser) Proline (Pro) Threonine (Thr) Alanine (Ala) UAU UAC UAA UAG CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG ] Tyrosine (Tyr) Stop Stop Histidine (His) Glutamine (Gln) Asparagine (Asn) Lysine (Lys) Aspartic acid (Asp) Glutamic acid (Glu) UGU UGC UGA Stop UGG Tryptophan (Trp) CGU CGC CGA CGG AGU AGC AGA AGG GGU GGC GGA GGG ] 1. List the mRNA base codons for the amino acids listed below. 2. a) aspartate: Cysteine (Cys) Serine (Ser) U C Arginine (Arg) A G Arginine (Arg) U C Glycine (Gly) A G U C A G U MCAG А
Consider the Haworth projections of f-L-galactose and B-L-glucose shown here. ОН CH OH ОН ОН B-L-galactose enantiomers anomers OH diastereomers epimers ОН CH₂OH OH Which terms describe the relationship between these two sugars? ОН OH B-L-glucose

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• Draw the 2 anomeric ring structures for D-glucose, using CHO the information in the straight- н-с -он Но -с —н chain structure provided. In your Н-с -он figure, number each of the C H-C-OH ČH,OH atoms, and show the position of every OH group.