effect of crosslinks on an elastomer
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What is the effect of crosslinks on an elastomer and what is the structural explanation
for their effect? What would happen to the amount of stretch, hardness, strength, and
creep in an elastomer if the crosslink density were increased?
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- With the help of a diagram, contrast the stress-strain relationship with respect to ceramic and metalsWith the help of a diagram, contrast the stress-strain relationship with respect to ceramic and metalsA specimen of steel has a rectangular cross section 20 mm wide and 40 mm thick, an elastic modulus of 207 GPa, and a Poisson's ratio of 0.30. If this specimen is pulled in tension with a force of 60,000 N, what is the change in width if deformation is totally elastic? O Increase in width of 3.62 x 10-6 m O Decrease in width of 7.24 x 10-6 m Increase in width of 7.24 x 106 m O Decrease in width of 2.18 x 10-6 mFatigue strength for non- ferrous materials in defined at stress cycles 10^3 10^5 10^7 10^9
- Given your understanding of what initiates and controls failure in materials, which of the following will increase the failure strength or lifetime of a test piece or component and why? a. Decreasing the difference between the maximum and minimum stress values, as this effects the stress concentration factor b. Decreasing the temperature below the brittle-ductile transition temperature, to make it harder C. Polishing to reduce surface defects Od. Increasing its volume, to give a larger cross sectional area Oe. Increasing the grain size so there are less grain boundaries to initiate failureBriefly explain the (a) how and (b) why the size of elastic deformation changes as the thickness of the specimen increases when a rod-shaped specimen made of the same material is bent.A copper rod is deformed using a uniaxial tensile force of 16000 N. Deformation continues until sufficient strain hardening has occurred such that the applied force is too small to allow further deformation. After deformation, the rod has a diameter of 0.01 m and a length of 1.5 m. Assume that copper follows the strain hardening lawwith K of 310 MPa and n=0.54 Please calculate the true strain after the deformation ?
- Question No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until fracture. Determine the following for the two metals (show all calculations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 m/m. c. Ultimate strength d. Modulus of resilience e. Toughness f. Which metal is more ductile? Why? 000 -Metal A S 600 -Metal B 300 0.00 a.02 0.04 0.06 0.08 0.10 0.12 0.14 Strain, mim FIGURE P1.16 Stress, MPaDraw a tensile stress-strain curve for a typical semi-crystalline polymer such as LLDPE, and define the three main regions on the curve.A material has the stress–strain behavior shown in Figure What is the material strength at rupture? What is the toughness of this material?
- 4. A 2.0 m steel is being subjected into a tensile test. At force 30 kN, the length of the steel is now 2.2 m, but after the force has been released, the steel returned to 2.1 m. The state of the steel is at?S Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until fracture. Determine the following for the two metals (show all calculations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 m/m. c. Ultimate strength d. Modulus of resilience e. Toughness f. Which metal is more ductile? Why? 900 Metal A 600 Metal B 300 0.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14 Strain, m/m FIGURE P1.16 Stress, MPaA bronze rod is rigidly attached between an aluminum rod and a steel rod as shown in the figure below. Axial loads are applied at the positions indicated. a) Find the maximum value of P that will not exceed a stress in steel of 140 MPa, in bronze of 100 MPa, or in aluminum of 90 MPa. b) Determine the deformation of the bronze rod if the value of P is 22.50 KN. The moduli of elasticity are 200 GPa for steel, 80 GPa for bronze and 70 GPa for aluminum.