Fe (s) + 2H+ (aq) → Fe²+ (aq) + H₂(g) Express your answer in volts to two decimal places. E cell = Submit Part C E cell = IVE ΑΣΦ Submit Request Answer O₂ (g) + 4H+ (aq) + 2Zn (s) → 2H₂O (1) +2Zn²+ (aq) Express your answer in volts to two decimal places. 15. ΑΣΦ WE ? Request Answer ? V V
Fe (s) + 2H+ (aq) → Fe²+ (aq) + H₂(g) Express your answer in volts to two decimal places. E cell = Submit Part C E cell = IVE ΑΣΦ Submit Request Answer O₂ (g) + 4H+ (aq) + 2Zn (s) → 2H₂O (1) +2Zn²+ (aq) Express your answer in volts to two decimal places. 15. ΑΣΦ WE ? Request Answer ? V V
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.80QP: Calculate the standard cell potential of the cell corresponding to the oxidation of oxalic acid,...
Related questions
Question
Transcribed Image Text:Calculate the standard cell potential for each of the
electrochemical cells.
Standard electrode potentials at 25 °C
Half-reaction
E (V)
Ag+ (aq) +e → Ag(s)
0.80
Pb2+ (aq) + 2e → Pb(s)
-0.13
Zn²+ (aq) +2e → Zn(s)
-0.76
0.00
2H+ (aq) +2e → H₂(g)
ClO₂(g) +eClO₂ (aq)
0.95
I2(s) +2e → 21 (aq)
0.54
Fe²+ (aq) + 2e → Fe(s)
-0.45
O₂(g) + 4H+ (aq) + 4e¯ → 2H₂O(1) 1.23
Cu²+ (aq) +2e →→ Cu(s)
0.34
Fe (s) + 2H+ (aq) → Fe²+ (aq) + H₂ (g)
Express your answer in volts to two decimal places.
E cell
Submit
Part C
E cell
=
ΠΫΠΙ ΑΣΦ
O₂ (g) + 4H+ (aq) +2Zn (s) → 2H₂O (1) +2Zn²+ (aq)
Express your answer in volts to two decimal places.
[Π| ΑΣΦ
Submit
Request Answer
?
Request Answer
?
V
V
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