Fill in the table regarding the hole and shaft below. Assume ANSI tolerancing.
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Fill in the table regarding the hole and shaft below. Assume ANSI tolerancing.
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- Ca Time Vol C. المعل من المنحني Clelall Jaal m'/sec. 10 m/sec. 104 m 102 m10 No sec. 0.0 74 534 0.074 ME 0-377 O-0738 O.0735 397 0-827 24.4311.9 O-5 s5-5 13-4 6.683. 44 10.8 0.56 45 11.54 48 O-354 4.39 0.325 0-o729 3-子子|0-275 0-413 5-45 O -o720 3 -320-244 32 30-7 ア.5 0:073 o.076 So1-9||+つーる .1子3ネ S-S|e 0 207 3o-74 2-01 o-153 2- Draw the relationship between Qact and H on: * Ordinary graph paper Logarithmic paper and Find the relationship Qact=KH where K=Qact when H=1, To find the adjusted Cd of the curve : Cd=Qact/Qthdi2.00 PI5. 50 d15. 60 15. 46 10. 06 INVD, UTE SPLIME DATA DETMETTED HARP CORNERT L47 10.04. ®sEr HEAT TREATi%TA lI. In. 1 1:19 و أمتحان يومي.pdf Fox flow mate 28 Lis Sind EL. 60M puup Power 150 Mm El. 30M Scanned by CamScanner
- Plz, solve this problem properly with detail?, it is not graded question. Four digits of reg.no : 5395BASIC MACAINING M12 X 1.75 k 50.80 101.60 A 203.20 8.30> UNIT: MM CALCULATE THE FF: (SHOW YOUR SDUATION) 1. Taper Per Inch ,tpi 2. Taper Per Foot, tpf 3. Taper Per centimeter ,tpcm 4. Taper Angle. Cantuitive methodology (seize and fox) noting they will be different. olowing cases, find the degrees-of-freedom using KMOGE (Identify L. h. Jz and M) and using the em 3: KMOGE has conditions under which it simply produces the wrong answer. In each of the A. L= Mseize and Fix B L = MKMOGE = Mseize and Fix J = MEMOGE Msetze and Fix
- 6736.6 is incorrectuonsanh 9m A marine engine cylinder has a compression ratio (r) of 9.5, a clearance volume of 650 cm3 and a piston stroke length of 675 mm. What is the bore diameter in millimetres (mm) for the engine cylinder. Give your answer to the nearest millimetre mm.H.W\ Calculate the excavation volume from the details of cross sections shown in table below. The width of the road is 12m Stations Cross-sections 60+40 C1.62 C2.07 C1.75 C2.01 C2.46 6.93 4.5 4.5 8.19 60+90 C2.24 C2.24 C2.24 9.36 9.36 70+55 C2.13 C2.03 C1.92 9.2 0. 8.88
- 1. Fill in the blanks according to the given information Hole Shaft 040 0. 025 025 +0. 021 025 +0. 006 040 -0. 009 -0. 025 -0.007 nominal size D, d upper limit of size Dmax/dmax lower limit of size Dmin/dm in upper limit deviation ES/es lower limit deviation El/ei Fundamental deviation Tolerance T/T. D d10 show complete STEP BY STEP solution, and draw a FBD.Calculate the Resultant Condition of the HOLE in the drawing below: 1.000 O 1.060 O 1.000 O.530 .982 C 2.000 Ø.995-1.000 +0.008MABC 6.00 O None of these answers is correct X 3.000 Y 01.005-1.030 +0.005MABC B A XX = .01 ANGLES = ± 1°