| Find a particular solution of the indicated linear system that satisfies the initial conditions x4 (0) = 5, x2 (0) = 2, and x3 (0) = 6.-13-17 -1-2- 3t4tx' =X, Xq =1210 14- 10 - 102The particular solution is x (t) = , ×2(t) = _, and x3(t) = []

Answered: Find a particular solution of the…

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter5: Systems Of Equations And Inequalities

Section: Chapter Questions

Problem 5CC

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Explain the steps for solving a system of equations using Cramer’s rule.
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Suppose the coal and steel industries form a closed economy. Every $1 produced by the coal industry requires $0.30 of coal and $0.70 of steel. Every $1 produced by steel requires $0.80 of coal and $0.20 of steel. Find the annual production (output) of coal and steel if the total annual production is $20 million.
Find a system of two equations in three variables, x1, x2 and x3 that has the solution set given by the parametric representation x1=t, x2=s and x3=3+st, where s and t are any real numbers. Then show that the solutions to the system can also be written as x1=3+st,x2=s and x3=t.
Redo Exercise 5, assuming that the house blend contains 300 grams of Colombian beans, 50 grams of Kenyan beans, and 150 grams of French roast beans and the gourmet blend contains 100 grams of Colombian beans, 350 grams of Kenyan beans, and 50 grams of French roast beans. This time the merchant has on hand 30 kilograms of Colombian beans, 15 kilograms of Kenyan beans, and 15 kilograms of French roast beans. Suppose one bag of the house blend produces a profit of $0.50, one bag of the special blend produces a profit of $1.50, and one bag of the gourmet blend produces a profit of $2.00. How many bags of each type should the merchant prepare if he wants to use up all of the beans and maximize his profit? What is the maximum profit?

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Find a particular solution of the indicated linear system that satisfies the initial conditions X₁ (0) = 5, X₂ (U) -13-17 -2 3 -3t x' = G-¤-|-| 10 14 2 x; x₁ = e H - 10 - 10 2 2 The particular solution is x₁ (t) = x₂(t)=[ and x3 (t) =