For steel, the energy to produce tensile failure is 105Jm 2 (i.e. fracture energy), modulus of elasticity 200 x 10°NM2. Thus if steel is to have cracks which do not propagate when a stress of 50 x10°Nm 2 is applied then what is the maximum crack length allowable 1.3m 50mm O 50 x10-9m 5um

For steel, the energy to produce tensile failure is 105Jm 2 (i.e. fracture energy), modulus of elasticity 200 x 10°NM2. Thus if steel is to have cracks which do not propagate when a stress of 50 x10°Nm 2 is applied then what is the maximum crack length allowable 1.3m 50mm O 50 x10-9m 5um

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)

Section: Chapter Questions

Problem 8.2.8P: A spherical steel pressure vessel (diameter 500 mm, thickness 10 mm) is coated with brittle lacquer...

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Concept explainers

Metrology of surface finish

In general terms, the application of scientific principles in the study of measurements is known as metrology. When speaking about measurement, it could be of time, length, microstructures, grain structures, internal crystal discontinuities, surface roughness, measurements of angles, height, width, and so on. While coming to the domain of mechanical engineering, metrology is considered the science of measurements of surface finish, length, surface texture, and angles.

Question

Which one is correct and why please ?

For steel, the energy to produce tensile failure is 10°Jm 2 (i.e. fracture energy), modulus of
elasticity 200 x 10°Nm 2. Thus if steel is to have cracks which do not propagate when a stress
of 50 x10 Nm 2 is applied then what is the maximum crack length allowable
1.3m
50mm
O 50 x10-9m
O 5um

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