For the reaction HNC(g) → HCN (g) K = 8.0 If the initial concentration of HNC is 0.80 M, what is the equilibrium concentration of HCN? Express your answer to two significant figures.
For the reaction HNC(g) → HCN (g) K = 8.0 If the initial concentration of HNC is 0.80 M, what is the equilibrium concentration of HCN? Express your answer to two significant figures.
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter17: Equilibrium
Section: Chapter Questions
Problem 7ALQ: The value of the equilibrium constant, K, is dependent on which of the following? (There may be more...
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![Question 8
For the reaction
HNC(g) → HCN(g)
If the initial concentration of HNC is 0.80 M, what is the equilibrium
concentration of HCN? Express your answer to two significant figures.
[HNC] = 0.71 X M
K = 8.0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc1eb37bf-1045-43dd-a351-de2d9ca4d2a5%2Fd7f2e077-11f4-497b-a5c1-a06431fb133c%2Fxu7i8h8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 8
For the reaction
HNC(g) → HCN(g)
If the initial concentration of HNC is 0.80 M, what is the equilibrium
concentration of HCN? Express your answer to two significant figures.
[HNC] = 0.71 X M
K = 8.0
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