Given: m∠AOB=42∘ m∠EOF=66∘ Prove: m∠COD=72∘ Complete the proof. It is given that m∠AOB=42∘ and m∠EOF=66∘ . By the , ∠EOF≅ ∠BOC . Therefore, m∠BOC=66∘ . By the , m∠AOC=108∘ , and by the , m∠AOC+m∠COD=180∘ . After application of the , m∠COD=72∘ .

Given: m∠AOB=42∘ m∠EOF=66∘ Prove: m∠COD=72∘ Complete the proof. It is given that m∠AOB=42∘ and m∠EOF=66∘ . By the , ∠EOF≅ ∠BOC . Therefore, m∠BOC=66∘ . By the , m∠AOC=108∘ , and by the , m∠AOC+m∠COD=180∘ . After application of the , m∠COD=72∘ .

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter1: Introduction To Algebra

Section1.8: Number Lines

Problem 45WE

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Question

Given:	m∠AOB=42∘ m∠EOF=66∘
Prove:	m∠COD=72∘

Given:

m∠AOB=42∘

m∠EOF=66∘

Prove:

m∠COD=72∘

Complete the proof.

It is given that m∠AOB=42∘ and m∠EOF=66∘ . By the , ∠EOF≅ ∠BOC . Therefore, m∠BOC=66∘ . By the , m∠AOC=108∘ , and by the , m∠AOC+m∠COD=180∘ . After application of the , m∠COD=72∘ .

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