Here is a function that is supposed to return True if word (any string) ends with "s" and False otherwise: def ends_with_s(word): if len(word) < 1: return False return word[-1] == "s" Here is the test function I am using to test ends_with_s: def test_ends_with_s(): assert(ends_with_s("cats")) # option 1 assert(ends_with_s("") is False) # option 2 assert(ends_with_s("apple") is False) # option 3 assert(ends_with_s("S")) # option 4 Rewrite ends_with_s so that the test

Here is a function that is supposed to return True if word (any string) ends with "s" and False otherwise: def ends_with_s(word): if len(word) < 1: return False return word[-1] == "s" Here is the test function I am using to test ends_with_s: def test_ends_with_s(): assert(ends_with_s("cats")) # option 1 assert(ends_with_s("") is False) # option 2 assert(ends_with_s("apple") is False) # option 3 assert(ends_with_s("S")) # option 4 Rewrite ends_with_s so that the test

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 6PE

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The international standard letter/number mapping for telephones is: Write a function that returns a number, given an uppercase letter, as follows:def getNumber(uppercaseLetter):Write a test program that prompts the user to enter a phone number as a string. The input number may contain letters. The program translates a letter (uppercase or lowercase) to a digit and leaves all other characters intact. Here is a sample run of the program: Enter a string: 1-800 flowers1-800-3569377
Scrabble Scrabble is a game where players get points by spelling words. Words are scored by adding together the point values of each individual letter. Define a function scrabble_score (word:str) -> int that takes a string word as input and returns the equivalent scrabble score for that word. score = {"a": 1, "c": 3, "f": 4, "i": 1, "1": 1, "o": 1, "r": 1, "u": 1, "t": 1, "x": 8, "z": 10} For example, "b": 3, "h": 4, "n": 1, Your Answer: == 20 assert scrabble_score("quick") assert scrabble_score("code") == 7 1 # Put your answer here 2 Submit "e": 1, "d": 2, "g": 2, "k": 5, "j": 8, "m": 3, "q": 10, "p": 3, "s": 1, "w": 4, "v": 4, "y": 4,
python only** define the following function: This function accepts a string as its only parameter, and it must return a tuple containing first the length of the string, and then the string itself. Define lengthAndValue with 1 parameter Use def to define lengthAndValue with 1 parameter Use a return statement Within the definition of lengthAndValue with 1 parameter, use return _in at least one place. Do not use any kind of loop Within the definition of lengthAndValue with 1 parameter, do not use any kind of loop.
please code in python Write a function that receives a string and a number (n) as parameters and returns a new string that contains only every nth letter from the given string. print(everyNth('banana', 2)) # should return aaaprint(everyNth('carrot', 3)) # should return rtprint(everyNth('pear', 1)) # should return pear
please code in python:def best(len_score,lst): max1=0 for i in reversed(lst): temp = len_score(i) if temp >= max1: max1 = temp ans = i return ans The best function should be able to take any scoring function and return the result. Define a function, number_of_vowels, that returns the number of vowels in a string. Pass it to your best function to find the name in names with the most vowels. See how easy it is to change the score function for different functionalities! Example: names = ["Ben", "April", "Zaber", "Alexis", "McJagger", "J.J.", "Madonna"] best(number_of_vowels, names) -> 'Alexis'
Problem: Substring Pattern Matching Input: A text string t and a pattern string p Output: Does t contain the pattern p as a substring, and if so, where? For example: with t= abaababbaba, p = abba, your function should return 5. int findmatch(char *p, char *t) { int plen = strlen(p); // len of string int tlen = strlen(t); // len of string t //TODO: your code } Analyze your algorithm: what is the big O?
Write a function is_mirror(s) that takes as input a string s and returns True if s is a mirrored string (i.e., a string that could have been produced by your mirror function) and False otherwise. Examples:>>> is_mirror('baconnocab')True>>> print(is_mirror('baconnoca'))False
Write a function that finds the number of occurrences of a specified character in a string using the following header:def count(s, ch):The str class has the count method. Implement your method without using the count method. For example, count("Welcome", 'e') returns 2. Write a test program that prompts the user to enter a string followed by a character and displays the number of occurrences of the character in the string.
Language: JAVA Script Write a function 'mostFrequentLetter(string)' that takes a string as an argument and returns the character that appears the most often. In case of a tie, you may return any of the characters. The string will have at least one character. Examples: console.log(most Frequent Letter ("apple")); // "p" console.log(mostFrequentLétter("banana")); // "a" console.log(mostFrequentLetter("What about a longer string?")); //" " **************************************************************/ function mostFrequentLetter(string) { |// Your code here} /****DO NOT MODIFY ANYTHING UNDER THIS LINE****/ try{| module.exports = mostfrequentletter;}catch (e) {|module.exports=null;}
Complete the check_strings_same_start(word1, word2) function which is passed two string parameters. The function returns True if the two parameter strings start with the same character and only one (not both) of the parameter strings has an even number of characters (including any space characters), otherwise the function returns False. For example: Test Result result = check_strings_same_start("blue", "bag") True print(result) print(check_strings_same_start("babyproofing", "baby")) False print(check_strings_same_start("check", "fact")) False
write the following as a function that takes in a string and returns a string. for (int i=0; i != user_string. size(); i++){ if (islower(user_string[i])){ user_string[i]=toupper(user_string[i]); } elseif(isupper(user_string[i])){ user_string[i]=tolower(user_string[i]); } } cout<<user_string; return0; }
1- Write a function that takes a word less than 25 characters long and returns the letter that word starts with (in capital letters). Frank starts with the letter F. 2- Write a function that has a string as formal parameter. The function then replaces all spaces and punctuation marks in the string with the asterisk (*). Here is a sample run: Nothing is impossible, the word itself says 'I'm possible'! Nothing*is*impossible**the*word*itself*says**I*m*possible** 3- Write a function that takes as input one line and reverses the words of the line. For example, birds and bees Reversed: bees and birds 4- Write a function that takes nouns (a string) as inputs and forms their plurals based on these rules: a. If noun ends in "y", remove the "y" and add "ies". b. If noun ends in "s","ch", or "sh", add "es". c. In all other cases, just add "s". (Test on the following: chair dairy boss circus fly dog church clue dish) chairs dairies bosses circuses flies dogs churches clues dishes Now create the…