A. Find Liquid LimitB. Find Plastic LimitC. Plasticity IndexD. Liquidity Index LIQUID LIMIT TESTTEST NO.14.No. of Blows39232013.Wt. of Wet Soil + Container (g)22.4621.1921.2726.12Wt. of Dry Soil + Container (g)19.4418.7818.7522.1Wt. of Container (g)12.7413.2413.2613.27

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Answered: LIQUID LIMIT TEST TEST NO. 4. No. of…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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WW Water Treatment II- 15th May 2022- Third Class- Pollution Control Branch US 3 Q1: AP. 5 Vs Determine the terminal settling velocity for a sand particle with an average diameter of 0.5 mm and a density of 2600 kg/m³ settling in water at 20°C. μ = 1.002 × 10-³ N-s/m² Pw= 998.2 kg/m³ 8(pp-P.) d 18μ U₂ RePwVsdp/H, Cp- = Stock 3 24 + N +0.34
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A soil speCimen has the Fullowing properties- gradahon apeninscmm) frehained seileqm) Sieve meiss a.425 2.00 280 Noz0 0.85 180 140 No 50 240 Nopo レ/5 166 No 200 . 075 200 Pan * plashicily L35 Classiy the seil auording to the Unified Seil Clasificaion System PL-26 CU.S.C.S.) Note: This quiz is lo be answered in the day and nght studies.(All groups) by all studenti quiz previously dane by groups A 4B will be ignored and, the guiz gven above will fe regerded inslead. The
The portion of soil passing through the No. 200 sieve is 95% and it has a liquid limit of 60 and plasticity index of 40. Classify the soil by the AASHTO system. a.A-6 (5) b.A-5 (6) c.A-4 (5) d.A-7-6 (20)
Problem 3 The following data shows the results of the liquid limit and the plastic limit test a. What is the water content of the soil for test No.3 based on the liquid? b. What is the plastic limit of the soil sample? What is the plasticity index of the soil sample if the liquid limit is 43? C.
Question 1 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 99 No. 8 2.380 91 No. 10 2.000 90 No. 20 0.840 85 No. 40 0.420 81 No. 60 0.250 79 No. 100 0.150 67 No. 200 0.075 60 Characteristics of No. 40 Fraction LL 39 PL 32 General classification Granular materials (35% r less of total sample passing No. 200) A-1 A-2 Group classification A-1-a A-1-b A-3 A-2-4 A-2-5 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 No. 40 No. 200 50 max. 30 max. 15 max. 50 max. 51 min. 25 max. 10 max. 35 max. 35 max. 35 max. 35 max. Characteristics of fraction passing No. 40 Liquid limit Plasticity index 40 max. 11 min. 40 max. 41 min. 41 min. 6 max. NP 10 max. 10 max. 11 min. Usual types of Stone fragments, Fine Silty or clayey gravel and sand General ciassification Granular materials (35% or less of total sample passing No. 200) A-1 A-2 Group classification A-1-a А-1-Ь A-3…
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Determine the oil surface elevation at section 1. Elevation =? 60 m 5= 2 k,- 0.040 mm D=0.1 m O Elevation = 130 m 7 m Oil, S= 0.9 v = 3 x 10-3 m2/s K = 0.5 Q= 0.03 m/s 130 m O Oil surface elevation at section 1 = 136 m O None of the answers are correct. O oil surface elevation at section 1 = 170.35 m O Oil surface elevation at section 1 = 175.35 m
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A municipal wastewater treatment plant employs three circular primary clarifiers arranged in parallel, following the bar screen and grit removal chamber. The plant receives 12 MGD. Each clarifier is center-fed (water enters at the center and exists at the perimeter).The clarifier radius is 56 ft and depth is 10 ft.What is the hydraulic loading rate (critical velocity) in each clarifier in units of ft3.ft-2.hr-1 ?
1. Percent passing on sieve 600um Weight Retained Individual Cumulative Percent Sieve (g) Percent Percent Passing 4.75mm 31.5 2.36mm 67.6 1.18mm 96.5 600um 111.1 300um 60.5 150um 115.6 75um 17.5 pan 31.5 O a. 38.70 O b. 36.70 O c. 34.70 O d. 40.70

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LIQUID LIMIT TEST TEST NO. 4. No. of Blows Wt. of Wet Soil + Container (g) Wt. of Dry Soil + Container (g) Wt. of Container (g) 39 23 20 13. 22.46 21.19 21.27 26.12 19.44 18.78 18.75 22.1 12.74 13.24 13.26 13.27