The angular position of a point on a rotating wheel is given by 0 = 5.96+ 5.36t + 2.08t, where e0. what are (a) the point's angular position and (b) its angular velocity? (c) What is its angular velcangular acceleration at t = 2.83 s. (e) Is its angular acceleration constant?(a) NumberUnits(b) NumberUnits(c) NumberUnits(d) NumberUnits(e) NumberYesNo The angular position of a point on a rotating wheel is given by e = 5.96+5.36t- + 2.08t°, where 0 is in radians and t is in seconds AttO what are (a) the point's angular position and (b) its angular velocity? (c) What is its angular velocity at t = 8.63 s? (d) Calculate itsangular acceleration at t = 2.83 s. (e) Is its angular acceleration constant?(a) NumberAUnits(b) NumberUnitsradrad/s(c) NumberUnitsrad/s 2kg-m^2N-mkg m^2/srad 2/s 2(d) NumberUnits(e) Number

Angular position = θ=5.96+5.93t2 +2.08t3

LISInsed What are (a) the point's angular position and (b) its angular velocity? (c) What is its angular velocity at t = 8.63 s? (d) Calcu angular acceleration at t= 2.83 s. (e) Is its angular acceleration constant? (a) Number Units (b) Number Uhits rad rads (c) Number Units rads2 kg-m2 kgim^2/s rad 2/5 2 (d) Number Units

LISInsed What are (a) the point's angular position and (b) its angular velocity? (c) What is its angular velocity at t = 8.63 s? (d) Calcu angular acceleration at t= 2.83 s. (e) Is its angular acceleration constant? (a) Number Units (b) Number Uhits rad rads (c) Number Units rads2 kg-m2 kgim^2/s rad 2/5 2 (d) Number Units

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 30P: A point on a rotating turntable 20.0 cm from the center accelerates from rest to a final speed of...

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