Interpret the generated results at 5% level of significance. Null Hypothesis: INF has a unit rootExogenous: ConstantLag Length: 2 (Automatic - based on SIC, maxlag=7)Augmented Dickey-Fuller test statisticTest critical values:1% level*MacKinnon (1996) one-sided p-values.Augmented Dickey-Fuller Test EquationDependent Variable: D(INF)Method: Least SquaresDate: 10/30/22 Time: 12:06Sample (adjusted): 1994 2021Included observations: 28 after adjustmentsVariableINF(-1)D(INF(-1))5% level10% levelD(INF(-2))сR-squaredAdjusted R-squaredS.E. of regressionSum squared residLog likelihoodF-statisticProb(F-statistic)CoefficientStd. Errort-Statistic-2.589635-3.689194-2.971853-2.625121t-Statistic2.505099 1.081088 2.317203Prob.*0.484740 Mean dependent var0.420332 S.D. dependent var1.183465 Akaike info criterion33.61415 Schwarz criterion-42.28868Hannan-Quinn criter.7.526140 Durbin-Watson stat0.0010210.1069-0.212713 0.082140 -2.589635 0.01610.5107890.156029 3.273673 0.00320.163446 -2.282174 0.0316-0.3730130.0293Prob.-0.2383571.5544113.3063343.4966493.3645151.914734

From the first table, we see that the p-value of Augmented Dickey Fuller test is 0.1069 which is…

Answered: Null Hypothesis: INF has a unit root…

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter7: Distance And Approximation

Section7.3: Least Squares Approximation

Problem 31EQ

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The output table below represents the results of the estimation of household expenditures (Y) and income (X) in thousand dollars. Considering the results, answer the following questions. Dependent Variable: Y Method: Least Squares Date: 01/07/16 Time: 11:22 Sample: 2000 2015 Included observations: 16 Variable Coefficient Std. Error t-Statistic Prob. C -0.241942 2.452237 -0.098662 0.9228 X 0.363176 0.013890 26.14674 0.0000 R-squared 0.979933 Mean dependent var 55.43750 Adjusted R-squared 0.978499 S.D. dependent var 33.17221 S.E. of regression 4.864079 Akaike info criterion 6.118100 Sum squared resid 331.2297 Schwarz criterion 6.214674 Log likelihood -46.94480 Hannan-Quinn criter. 6.123046 F-statistic 683.6522 Durbin-Watson stat 0.632113…
On minitab or excel Calculating the coefficient of determination of a set of data, it was obtained that r^2 = 0.845 . Based on this value, it can be concluded that: Options: The least squares line provided a good fit as a large proportion of the variability in "y" has been explained by the least squares line. The least squares line provided a good fit as a small proportion of the variability in "y" has been explained by the least squares line. The least squares line did not provide a good fit since a small proportion of the variability in "y" has been explained by the least squares line. The least squares line did not provide a good fit since a large proportion of the variability in "y" has been explained by the least squares line.
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The output table below represents the results of the estimation of household expenditures (Y) and income (X) in thousand dollars. Considering the output table below, answer the following questions. Dependent Variable: Y Method: Least Squares Date: 12/28/16 Time: 15:29 Sample: 2000 2010 Included observations: 11 Variable Coefficient Std. Error t-Statistic Prob. C 0.229334 2.938536 0.078044 0.9395 X 0.354833 0.024783 14.31783 0.0000 R-squared 0.957944 Mean dependent var 37.45455 Adjusted R-squared 0.953271 S.D. dependent var 21.01125 S.E. of regression 4.541976 Akaike info criterion 6.027567 Sum squared resid 185.6659 Schwarz criterion 6.099911 Log likelihood -31.15162 Hannan-Quinn criter. 5.981964…
You are interested in investigating the factors that influence the returns of the mining company Meddi Ltd. You have reason to believe that the company EPS, the rate of inflation and interest rates have an impact on the performance if this company, and to test this claim, you run a regression. The regression results are displayed below. Dependent Variable: LMEDDI Method: Least Squares Date: 18/04/22 Time: 14:26 Sample (adjusted): 1995M08 2021M12 Included observations: 124 after adjustments Each variable has been transformed into log form so they can be interpreted as percentages where: LMEDDI = natural log of Meddi Ltd returns LCPI = natural log of the inflation rates LINT = natural log of the interest rates a) Write out this regression equation. b) Test for the statistical significance of each explanatory variable in the model at the 5% level of significance and comment on the effect each variable has on the MEDDI stock returns. Show all workings.
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In Austria ,The amount of money spent on the restoration of a sanctuary and the distinct kangaroo populations present appeared to have negative correlations For investigation of this onserved assocaition ,what can a resecher do to begin his research 1Conduct an experiment 2Calculate the squares of coreealtion coefficient 3Calculate the least squares regression line 4 calculate the corelation coefficient Explain answer in 1 or 2 lines
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Interpreting technology: The following display from the TI-84 Plus calculator presents the least-squares regression line for predicting the price of a certain stock y from the prime interest rate in percent x LinReg y=+a+bx a=2.29525776 b=0.38970413 r^2=0.4319044662 r=0.65719439 What is the correlation between the interest rate and the yield of the stock?

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