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Octasulfur (S8) decomposes at high temperatures to form oxygen and sulfur trioxide:   _____S8 + _____O2              _____SO3   Balance the chemical equation. If it is already balanced, leave it blank or put 1s. How many grams of octasulfur (S8) will I need to form 89 liters of sulfur trioxide?

Octasulfur (S8) decomposes at high temperatures to form oxygen and sulfur trioxide:   _____S8 + _____O2              _____SO3   Balance the chemical equation. If it is already balanced, leave it blank or put 1s. How many grams of octasulfur (S8) will I need to form 89 liters of sulfur trioxide?

Living By Chemistry: First Edition Textbook
Living By Chemistry: First Edition Textbook
1st Edition
ISBN:9781559539418
Author:Angelica Stacy
Publisher:Angelica Stacy
ChapterU4: Toxins: Stoichiometry, Solution Chemistry, And Acids And Bases
Section: Chapter Questions
Problem SV2RE
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  1. Octasulfur (S8) decomposes at high temperatures to form oxygen and sulfur trioxide:

 

_____S8 + _____O2              _____SO3

 

  1. Balance the chemical equation. If it is already balanced, leave it blank or put 1s. How many grams of octasulfur (S8) will I need to form 89 liters of sulfur trioxide?
  2.  
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