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One point charge of +5.9 nC is at x=3cm, y=0, z=0, and one charge of -5.9 nC is at x=-3cm, y=0, z=0. Find the electric potential due to these charges at (a) x=3cm, y=8cm, z=0; (b) x=-3cm, y=8cm z=0. Take V=0 at infinity. A. a) V = + 133 V b) = -133 VB. a) V = - 133 V b) = +133 VC. a) V = + 99V b) = -120 VD. a) V = - 120 V b) = -99 V

One point charge of +5.9 nC is at x=3cm, y=0, z=0, and one charge of -5.9 nC is at x=-3cm, y=0, z=0. Find the electric potential due to these charges at (a) x=3cm, y=8cm, z=0; (b) x=-3cm, y=8cm z=0. Take V=0 at infinity. A. a) V = + 133 V b) = -133 VB. a) V = - 133 V b) = +133 VC. a) V = + 99V b) = -120 VD. a) V = - 120 V b) = -99 V

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter16: Electrical Energy And Capacitance
Section: Chapter Questions
Problem 12P: The two charges in Figure P16.12 are separated by d = 2.00 cm. Find the electric potential at (a)...
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One point charge of +5.9 nC is at x=3cm, y=0, z=0, and one charge of -5.9 nC is at x=-3cm, y=0, z=0. Find the electric potential due to these charges at (a) x=3cm, y=8cm, z=0; (b) x=-3cm, y=8cm z=0. Take V=0 at infinity.

A. a) V = + 133 V b) = -133 V
B. a) V = - 133 V b) = +133 V
C. a) V = + 99V b) = -120 V
D. a) V = - 120 V b) = -99 V

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