Oppositely charged parallel plates are separated by 4.50 mm. A potential difference of 600 V exists between the plates.(a) What is the magnitude of the electric field between the plates?1.33e5✓N/C(b) What is the magnitude of the force on an electron between the plates?2.1286e-14✔N(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.94 mm from the positive plate?3.4909-17 X J

Potential difference between plate = V = 600v distance between plate = d = 4.5 mm = 4.5×10-3m

Oppositely charged parallel plates are separated by 4.50 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? 1.335 ✓N/C (b) What is the magnitude of the force on an electron between the plates? 2.1286e-14 ✔N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.94 mm from the positive plate? 3.4909e-17 x J

Oppositely charged parallel plates are separated by 4.50 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? 1.335 ✓N/C (b) What is the magnitude of the force on an electron between the plates? 2.1286e-14 ✔N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.94 mm from the positive plate? 3.4909e-17 x J

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter25: Electric Potential

Section: Chapter Questions

Problem 25.22P: The three charged particles in Figure P25.22 are at the vertices of an isosceles triangle (where d =...

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