Part 1: Let M solution to M = 2 0 5 5 -15 -5 48 -5 12 and let b= = 15 60 [24] 6 3 .There is a very obvious = b that you should be able to find by inspection. What is it?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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4
5
2
5
0
-15 15 60
solution to M = b that you should be able to find by inspection. What is it?
Part 1: Let M
=
-5 48
-5 12 and let b
Part 2: Use the fact that
24
6
3
=
.There is a very obvious
0
1
I
1
0
previous answer to write down all the solutions of Mb in parametric vector
form.
is a basis for the null space of A, together with your
Transcribed Image Text:4 5 2 5 0 -15 15 60 solution to M = b that you should be able to find by inspection. What is it? Part 1: Let M = -5 48 -5 12 and let b Part 2: Use the fact that 24 6 3 = .There is a very obvious 0 1 I 1 0 previous answer to write down all the solutions of Mb in parametric vector form. is a basis for the null space of A, together with your
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