Part A What is the speed of a proton after being accelerated from rest through a 4.4x107 V potential difference? Express your answer using two significant figures. ΜΕ ΑΣΦ ? 20 Submit Request Answer
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- A Van de Graaff accelerator utilizes a 50.0 MV potential difference to accelerate charged particles such as protons. (a) What is the velocity of a proton accelerated by such a potential? (b) An electron?In nuclear fission, a nucleus splits roughly in half, (a) What is the potential 2.001014 in from a fragment that has 46 protons in it? (b) What is the potential energy in MeV of a similarly charged fragment at this distance?Calculate the speed of a proton after it accelerates from rest through a potential difference of 275 V. Express your answer in meters per second. VG ΑΣΦ Up = Submit Part B Request Answer Ve C ? Calculate the speed of an electron after it accelerates from rest through a potential difference of 275 V. Express your answer in meters per second. VE ΑΣΦ m/s ? m/s
- A) Through what potential difference does an electron have to be accelerated, starting from rest, to achieve a speed of 0.965 cc? Express your answer in volts. B) What is the kinetic energy of the electron at this speed? Express your answer in joules. Express your answer in joules. C) What is the kinetic energy of the electron at this speed? Express your answer in electronvolts. Express your answer in electronvolts.A proton is accelerated through a potential difference of 6 MV. (megavolts) from rest. Calc. the final velocity in m/s (a) 1.4 X 10' (b) 2.4 X 10' (c) 3.4 X 10' (d) 4.4 X 10'.What is the speed of an electron after being accelerated from rest through a 2.5×107 V potential difference? Express your answer as a fraction of cc.
- An electron is accelerated from rest through a potential difference AV. If the electron reaches a speed of 7.00 x 106 m/s, what is the potential difference? Be sure to include the correct sign.Calculate the speed of an electron (in m/s) after it accelerates from rest through a potential difference of 140 V. 7.02e25 m/s The speed of the electron v can be found using the kinetic energy equation, K = 1/2(mv^2). The change in kinetic energy is equal to the work done on the electron, K = W = -U = -qV. Using those two equations, solve for the speed v in terms of the potential V and constants. Remember that the mass of an electron is 9.1e-31 kg and its charge is 1.6e-19 C. Submit Answer Incorrect. Tries 1/2 Previous TriesA proton is accelerated by a potential difference of 10 kV. How fast is the proton moving if it started from rest? A. 9.41 x 10-6 m/s B. 3.45 x 106 m/s C. 1.38 x 106 m/s D. 2.12 x 106 m/s Select one: О а. А O b. B О с. С d. D Clear my choice
- Suppose an electron (q= -e= -1.6x 10-19 C.m=9.1×10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 v. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U- Assuming all potential energy U is converted to kinetic energy K. K+U=0 K--U Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: 1/2 Plugging in values, the value of the electron's speed is: x 10' m/s... Path of trajectory AV w An electron is fired at a speed v¡ = 3.4 x 106 m/s and at an angle 0; = 30.5° between two parallel conducting plates as shown in the figure. If s = 1.5 mm and the voltage difference between the plates is AV = 98 V, determine how close, w, the electron will get to the %3D %3D bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. Round your answer to 6 decimal places.In large CRT televisions, electrons are accelerated from rest by a potential difference of 23.88 kV and shot onto a phosphorescent screen to produce an image. What is the speed of the electrons when they reach the screen? (g. = 1.602 x 10-19C ;me = 9.11 x 10 -31 kg) Answer: x10' m (express your answers in tenths place or one decimal digit only)