Part B Initially, 0.65 mol of PC15 is placed in a 1.0 L flask. At equilibrium, there is 0.13 mol of PC13 in the flask. What is the equilibrium concentration of PC15? Express your answer to two significant figures and include the appropriate units. [PC15] = HA Value Units ?

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Chapter12: Chemical Equilibrium
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POST) question 31.

please answer B and show work thank you 

Consider the following reaction:
PC15 (g) PC13 (g) + Cl₂(g)
Kc
Kc
Submit
Part B
=
[PC15] =
=
Submit
[PC13][C1₂]
[PC15]
Correct
The product concentrations are in the numerator of the equilibrium-constant expression, and the reactant concentration is in the
denominator of the expression. All coefficients in the balanced chemical equation are 1, so there are no exponents in the expression.
[PC15]
[PC13][C12]
Previous Answers
Initially, 0.65 mol of PC15 is placed in a 1.0 L flask. At equilibrium, there is 0.13 mol of PC13 in the flask. What is the equilibrium
concentration of PC15 ?
Express your answer to two significant figures and include the appropriate units.
O
µA
Value
Request Answer
Units
(@
?
Transcribed Image Text:Consider the following reaction: PC15 (g) PC13 (g) + Cl₂(g) Kc Kc Submit Part B = [PC15] = = Submit [PC13][C1₂] [PC15] Correct The product concentrations are in the numerator of the equilibrium-constant expression, and the reactant concentration is in the denominator of the expression. All coefficients in the balanced chemical equation are 1, so there are no exponents in the expression. [PC15] [PC13][C12] Previous Answers Initially, 0.65 mol of PC15 is placed in a 1.0 L flask. At equilibrium, there is 0.13 mol of PC13 in the flask. What is the equilibrium concentration of PC15 ? Express your answer to two significant figures and include the appropriate units. O µA Value Request Answer Units (@ ?
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