Part B involves the addition of sodium acetate in the reaction between 2.6- dimethylaniline and chloroacetyl chloride. Why is sodium acetate used in this step? ○ To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so less reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so less reactive To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so more reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so more reactive

Part B involves the addition of sodium acetate in the reaction between 2.6- dimethylaniline and chloroacetyl chloride. Why is sodium acetate used in this step? ○ To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so less reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so less reactive To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so more reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so more reactive

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter24: Carboxylic Acids & Derivatives

Section: Chapter Questions

Problem 16CTQ

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