Please help with the formulas for weighted distance in excel. H2A1 Location2 New York3 Maryland4 Virginia5 SC6 NC7 TN8 FL9 Ohio10 Wyoming11 CA12 Iowa13 IL14 Mass15 NJ16 PA171819 Coordinates location20 Decision VariablefixBlatClong40.714 -74.00639.026 -77.07637.432 -78.65732.216 -80.75335.772 -78.63935.961 -83.92127.499 -82.57539.136 -84.50343.623 -110.62634.019 -118.49141.699 -93.04741.850 -87.65042.934 -70.79840.901 -74.51439.952 -75.164X0Y0D#Relatives4382112166110741102EFGDistance Weighted Distance84.46622286.39310787.10929786.94178986.39256191.3009287.0332893.12573118.91618123.27808101.9632797.12855982.79938485.00172685.122172H Wedding Planning. The distance between two cities in the United States can be approximated bythe following formula, where lat₁ and long, are the latitude and longitude of city 1 and lat2 andlong, are the latitude and longitude of city 2:69 (lat₁ - lat₂)² + (long₁ − long₂)²Ted's daughter is getting married, and he is inviting relatives from 15 different locations in theUnited States. The file Wedding gives the longitude, latitude, and number of relatives in each of the15 locations. Ted would like to find a wedding location that minimizes the demand-weighteddistance, where demand is the number of relatives at each location. Assuming that the wedding canoccur anywhere, find the latitude and longitude of the optimal location. (Hint: Notice that alllongitude values given for this problem are negative. Make sure that you do not check the option forMake Unconstrained Variables Non-Negative in Solver.)

It is given that the weights in this question are the number of relatives at each location. The…

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Please help with the formulas for weighted distance in excel.

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter8: Introduction To Functions

Section8.10: Inverse Variation

Problem 8P

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Question

Please help with the formulas for weighted distance in excel.

H2
A
1 Location
2 New York
3 Maryland
4 Virginia
5 SC
6 NC
7 TN
8 FL
9 Ohio
10 Wyoming
11 CA
12 Iowa
13 IL
14 Mass
15 NJ
16 PA
17
18
19 Coordinates location
20 Decision Variable
fix
B
lat
C
long
40.714 -74.006
39.026 -77.076
37.432 -78.657
32.216 -80.753
35.772 -78.639
35.961 -83.921
27.499 -82.575
39.136 -84.503
43.623 -110.626
34.019 -118.491
41.699 -93.047
41.850 -87.650
42.934 -70.798
40.901 -74.514
39.952 -75.164
X
0
Y
0
D
#Relatives
43
8
2
1
12
1
6
6
1
10
7
4
1
10
2
E
F
G
Distance Weighted Distance
84.466222
86.393107
87.109297
86.941789
86.392561
91.30092
87.03328
93.12573
118.91618
123.27808
101.96327
97.128559
82.799384
85.001726
85.122172
H

Wedding Planning. The distance between two cities in the United States can be approximated by
the following formula, where lat₁ and long, are the latitude and longitude of city 1 and lat2 and
long, are the latitude and longitude of city 2:
69 (lat₁ - lat₂)² + (long₁ − long₂)²
Ted's daughter is getting married, and he is inviting relatives from 15 different locations in the
United States. The file Wedding gives the longitude, latitude, and number of relatives in each of the
15 locations. Ted would like to find a wedding location that minimizes the demand-weighted
distance, where demand is the number of relatives at each location. Assuming that the wedding can
occur anywhere, find the latitude and longitude of the optimal location. (Hint: Notice that all
longitude values given for this problem are negative. Make sure that you do not check the option for
Make Unconstrained Variables Non-Negative in Solver.)

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