Problem 4: Solve the nonhomogeneous wave equation c2urz +F(x,t) = utt, 0 < x < L, t> 0, u(0, t) = 0, u(L, t) = 0 u(x,0) = f(x), u(x, 0) = 0
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- for wave equation, seperation of vairables u(x,t)=X=(x)T(t)2. The position vector of a particle is given by r(t)= (2 cos t sin t)i +(cos^2 t - sin^2 t)j + (3t)k If the particle begins its motion at t = 0 and ends at t = pi, find the difference between the length of the path traveled and the distance between start position and end position8) Find the position vector r(t) for a particle with acceleration a(t) = (5t, 5 sin t, cos 6t), initial velocity (0) = (3, -3, 1) and initial position (0) = (5, 0, -2).
- 3. Triangle DEF with vertices D(0, 6). E(3, 5). and F(1, 1): 90° counterclockwise about the point (5, 2) D' L E' (L F'(LQ1:- Find the domain of the following vector functions:- (a) f (t) = (cos t)i – Ln(t)j + vt – 2k (b) f (t) = Ln|t – 1|i + e'j + vtk Q2:- Find the domain and the range of the following equations:- 1 -1 (1)W (2)W = sin x y (3)W x²+y2 ху 1 (4)W (5)W = /x² + y2 + z² (6) W = x – y x²+y2+z² (7)W = Ln(x² + y²) (8) W = xy (9) W = 4x² + 9y²The graph of f (θ) = Acos θ + B sin θ is a sinusoidal wave for any constants A and B. Confirm this for (A,B) = (1, 1), (1, 2), and (3, 4) by plotting f .
- Consider the wave equation 0 0, with u(0,1) = 1(xt)= 0, u(x,0) = sin x and =0 at t=0. Then u is13. The position vector of a particle at time t is R = cos (t – 1) i + sinh (t – 1) j + ark. If at t = 1, the acceleration of the particle be perpendicular to its position vector, then a is equal to 1 (a) 0 (b) 1 (c) 2 (d) (AMIETE, Dec. 2009) Ans. (d)3.8. Question. Match equations y' = sin x, y' = cos y, y' = y cos(x)· a) c) b) to direction fields. Justify.
- 4. A wheel is rotating about the line y = x, z = 0 with angular speed w = 10 sec-. Find the velocity and speed of a body at the point (4, 2,-2). | 5. v = y, -x is the velocity field of a body moving along a path. Find the corresponding equation of the path in the cartesian coordinates and assign v to various points of the path.Ř(t) = cos(2t)â + sin(2t)j + 4tk %3D Problem. Consider the helix (c) Find an equation for the plane containing the vectors R'(t) and R"(t) and passing through the point R(t), at every point t. (Hint: Your equation for the plane will involve t's (a) Compute R'(t) and R"(t) (b) Compute the curvature of R(t) at every point t. the plane changes as t varies.). P Type here to search LG Plese TEXAS TECH UNIVE MIsdiAoman Mender FSC wwww.fe. MIX from F9C C119908 IST AUDIO 29 46012 1Hem No. 46012 Norcom, Ino Griffin, GA 30224 www.norcominc.coo Made in Brazil nu לnatFind a vector parametric equation (t) for the line through the points P = (5, -5, -5) and Q = (10, -6, -9) for each of the given conditions on the parameter t. (a) If 7*'(0) = (5, -5, -5) and 7(8) (10, -6, -9), then r(t) (b) If 7 (5) = P and 7(9) F(t) = Q, then = (c) If the points P and Q correspond to the parameter values t = 0 and t = -2, respectively, then F(t)