Question 3. A marble is thrown horizontally with a speed of 19.2 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 39° with the horizontal. From what height above the ground was the marble thrown? Ans: 12.33 m 21.0 C40

Question 3. A marble is thrown horizontally with a speed of 19.2 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 39° with the horizontal. From what height above the ground was the marble thrown? Ans: 12.33 m 21.0 C40

Name: the court is the tennis ball when it leaves the racket? Ans: 1.83 mSU
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Description: the court is the tennis ball when it leaves the racket? Ans: 1.83 mSULdes BudQuestion 3. A marble is thrown horizontally with a speed of 19.2 m/s from the top of abuilding. When it strikes the ground, the marble has a velocity that makes an angle of

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter4: Motion In Two And Three Dimensions

Section: Chapter Questions

Problem 76P: A small plane flies at 200 km/h in still air. If the wind blows directly out of the west at 50 km/h,...

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A cannonball is shot with an initial speed of 30.0 m/s and 25.0º angle above horizontal from a height of 12.0 m. How far can the cannonball go horizontally when it lands on the ground, in meters? Use g = 10.0 m/s2. (Hint: Clearly label quantities along x- and y- components and write down all steps.) inknow the answer is 89 but I need the steps
Max Height = V;*sin's (visine) 28 28 Max Ronge = v? sin 20 Vi Height 8 = 9. 81 m/sz Range 1.) A very small cannon (very small, meaning we can disregard its size) has a muzzle velocity (velocity of the projectile as it leaves the barrel) of 30 m/s and is at an angle of 35° from the ground. a.) What is the Max Height? b.) What is the Range? Somple . Diagrom Vi = inital velocty cmuzzle velocity) 0 = ongle from the grond Vi = 30 m/e Height e= 350 Ronge a) Monx Height : (30) (ain 5) Max Height = V;? sin?e 28 15- 09 m R(9.81) b.) Ronge : v.* sin 20 (30)2 sin (70*) Ronge = 86.21M * Incicode your final answers. In this case, I used a box