Ring 1 has a radius R₁ = 9 cm and a charge Q₁ = 54 pC uniformly distributed over the ring. Ring 2 has a radius R₂ = 5 cm and linear charge density A2 = -50 pc/m. The rings are separated by a distance d = 20 cm. y [cm] R₁ Ring 1 OE₁= OE₁ = OE₁= E₁ = 1. E₁ = 3. Oright OLeft Oup Odown Q₂ = OE₂= OE₂= OE₂= R₁ d (9x109) (54-10-12).(9-10-2) ((9-10-2)²+(9-10-2)2)0.5 (9x109) (54-10-12)-(9) ((9)²+(9)2)1.5 The magnitude of the electric field created by ring 1 at point can be calculated by: (9x109) (54-10-12).(9-10-2) ((9-10-2)2+(9-10-2)2)¹.5 R₂ D Ring 2 The value of the magnitude of the electric field created by ring 1 at point A is: [N/C] x [cm] What is the direction of the electric field created by ring 1 at point A? The electric field created by ring 1 at point A is: î+( Ĵ[N/C] Calculate the total charge of ring 2 in Coulombs. [C] (9x109) (1.57x10-¹¹)-(0.11) ((0.11)2+(5-10-2)2)0.5 (9x109) (1.57x10-¹1)-(0.11) ((0.11)²+(5)2)0.5 The magnitude of the electric field created by ring 2 at point A can be calculated by: (9x109) (1.57x 10-11)-(0.11) ((0.11)²+(5-10-2)2)1.5 If the magnitude of the electric field created by ring 2 at point A is equal to E₂ = 7. 8.82x 10-12 [N/C], find the electric field vector created by the ring 2 at point A. E₂ = + Ĵ[N/C]
Ring 1 has a radius R₁ = 9 cm and a charge Q₁ = 54 pC uniformly distributed over the ring. Ring 2 has a radius R₂ = 5 cm and linear charge density A2 = -50 pc/m. The rings are separated by a distance d = 20 cm. y [cm] R₁ Ring 1 OE₁= OE₁ = OE₁= E₁ = 1. E₁ = 3. Oright OLeft Oup Odown Q₂ = OE₂= OE₂= OE₂= R₁ d (9x109) (54-10-12).(9-10-2) ((9-10-2)²+(9-10-2)2)0.5 (9x109) (54-10-12)-(9) ((9)²+(9)2)1.5 The magnitude of the electric field created by ring 1 at point can be calculated by: (9x109) (54-10-12).(9-10-2) ((9-10-2)2+(9-10-2)2)¹.5 R₂ D Ring 2 The value of the magnitude of the electric field created by ring 1 at point A is: [N/C] x [cm] What is the direction of the electric field created by ring 1 at point A? The electric field created by ring 1 at point A is: î+( Ĵ[N/C] Calculate the total charge of ring 2 in Coulombs. [C] (9x109) (1.57x10-¹¹)-(0.11) ((0.11)2+(5-10-2)2)0.5 (9x109) (1.57x10-¹1)-(0.11) ((0.11)²+(5)2)0.5 The magnitude of the electric field created by ring 2 at point A can be calculated by: (9x109) (1.57x 10-11)-(0.11) ((0.11)²+(5-10-2)2)1.5 If the magnitude of the electric field created by ring 2 at point A is equal to E₂ = 7. 8.82x 10-12 [N/C], find the electric field vector created by the ring 2 at point A. E₂ = + Ĵ[N/C]
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Chapter1: Units, Trigonometry. And Vectors
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![Problem 3.
The figure shows two rings with their central axes along the x-axis.
Ring 1 has a radius R₁ = 9 cm and a charge Q₁ = 54 pC uniformly distributed over the ring.
• Ring 2 has a radius R₂ = 5 cm and linear charge density A2 = -50 pc/m.
•The rings are separated by a distance d = 20 cm.
y [cm]
Ring 1
OE₁ =
OE₁=
2.
The magnitude of the electric field created by ring 1 at point A can be calculated by:
(9x109) (54-10-12)-(9-10-2)
OE₁ =
R₁
E₁=
3.
4.
Ē₁
Oright
OLeft
Oup
Odown
5.
Q₂
6.
OE₂=
OE₂=
OE₂=
((9-10-2)²+(9-10-2)2)¹.5
(9x109) (54-10-12) (9-10-2)
((9-10-2)2+(9-10-2)2)0.5
(9x109) (54 10-12) (9)
((9)²+(9)2)1.5
R₂
Ring 2
7.
8.82x 10
E₂ =
The value of the magnitude of the electric field created by ring 1 at point A is:
[N/C]
What is the direction of the electric field created by ring 1 at point A?
The electric field created by ring 1 at point A is:
î+
j [N/C]
(9x109) (1.57x10-¹1)-(0.11)
((0.11)²+(5)2)0.5
x [cm]
Calculate the total charge of ring 2 in Coulombs.
[C]
The magnitude of the electric field created by ring 2 at point A can be calculated by:
(9x109) (1.57x 10-11)-(0.11)
((0.11)²+(5-10-2)2)¹.5
(9x109) (1.57x10-¹1)-(0.11)
((0.11)²+(5-10-2)2) 0.5
If the magnitude of the electric field created by ring 2 at point A is equal to E₂ =
2 [N/C], find the electric field vector created by the ring 2 at point A.
Ĵ[N/C]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F621c65f8-44f1-4cab-98a0-cd79230825b8%2Fc56eed7c-1ebe-4642-afdc-6f15c564ea99%2F38sndsn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 3.
The figure shows two rings with their central axes along the x-axis.
Ring 1 has a radius R₁ = 9 cm and a charge Q₁ = 54 pC uniformly distributed over the ring.
• Ring 2 has a radius R₂ = 5 cm and linear charge density A2 = -50 pc/m.
•The rings are separated by a distance d = 20 cm.
y [cm]
Ring 1
OE₁ =
OE₁=
2.
The magnitude of the electric field created by ring 1 at point A can be calculated by:
(9x109) (54-10-12)-(9-10-2)
OE₁ =
R₁
E₁=
3.
4.
Ē₁
Oright
OLeft
Oup
Odown
5.
Q₂
6.
OE₂=
OE₂=
OE₂=
((9-10-2)²+(9-10-2)2)¹.5
(9x109) (54-10-12) (9-10-2)
((9-10-2)2+(9-10-2)2)0.5
(9x109) (54 10-12) (9)
((9)²+(9)2)1.5
R₂
Ring 2
7.
8.82x 10
E₂ =
The value of the magnitude of the electric field created by ring 1 at point A is:
[N/C]
What is the direction of the electric field created by ring 1 at point A?
The electric field created by ring 1 at point A is:
î+
j [N/C]
(9x109) (1.57x10-¹1)-(0.11)
((0.11)²+(5)2)0.5
x [cm]
Calculate the total charge of ring 2 in Coulombs.
[C]
The magnitude of the electric field created by ring 2 at point A can be calculated by:
(9x109) (1.57x 10-11)-(0.11)
((0.11)²+(5-10-2)2)¹.5
(9x109) (1.57x10-¹1)-(0.11)
((0.11)²+(5-10-2)2) 0.5
If the magnitude of the electric field created by ring 2 at point A is equal to E₂ =
2 [N/C], find the electric field vector created by the ring 2 at point A.
Ĵ[N/C]
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