rt algorithm Use ( 20 13 74 5 12 9 22 95 22 6 101 72 3 53 33 21 96) as input. To do that, calculate the average value of a sublist before dividing it. (quicksort ‘( 20 13 74 5 12 9 2
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Written in Dr Racket:
Write a recursive function that takes a list of numbers as input and returns a list of the numbers in ascending order.
Use the quicksort algorithm
Use ( 20 13 74 5 12 9 22 95 22 6 101 72 3 53 33 21 96) as input.
To do that, calculate the average value of a sublist before dividing it.
(quicksort ‘( 20 13 74 5 12 9 22 95 22 6 101 72 3 53 33 21 96))
returns ‘(3 5 6 9 12 13 20 21 22 22 33 53 72 74 95 96 101)
Do not use sort, quicksort, set!, or mean.
Step by step
Solved in 4 steps with 2 images
- Write a recursive function called that takes a string of single names separated by spaces and prints out all possible combinations (permutations), each combination on a new line. When the input is: Alice Bob Charlie then the output is: Alice Bob Charlie Alice Charlie Bob Bob Alice Charlie Bob Charlie Alice Charlie Alice Bob Charlie Bob Alice Here is my original code that needs to be fixed: def all_permutations(permList, nameList): # TODO: Implement method to create and output all permutations of the list of names. if nameList == len(permList) - 1: return nameList else: for x in range(permList, len(nameList)): permList[nameList], permList[x] = permList[x], permList[name_List] return all_permutations(permList, nameList + 1) permList[nameList], permList[x] = permList[x], permList[name_List] if __name__ == "main": nameList = input().split(' ') permList = [] all_permutations(permList, nameList)Write a function in a racket code that takes as input a list of elements and returns a list with elements and their position after. For example, if the input to the function is (list ’a ’b ’c) then it will return (list a 1 b 2 c 3). Make sure to use recursionWrite a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] ================================================ import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum = findMinimum(numbers);System.out.println("Minimum: " + minimum);}public static int…
- Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] Hint:The trick is to remove the last element each time to make the ArrayList a little shorter. import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum =…Complete the following recursive function that returns the sum of all the numbers in a list that are positive and even numbers. Replace the bold text with the correct expression. #lang racket (define (positiveEvenNums 1st) (if (null? 1st) (if (THE CAR OF THE LIST IS POSITIVE AND EVEN) (+ (car 1st) (positiveEvenNums (cdr 1st))) (positiveEvenNums (cdr 1st))))) (positiveEvenNums '(-3 8 4 3 -2 0 5))Write a recursive function called that takes a string of single names separated by spaces and prints out all possible combinations (permutations), each combination on a new line. When the input is: Alice Bob Charlie then the output is: Alice Bob Charlie Alice Charlie Bob Bob Alice Charlie Bob Charlie Alice Charlie Alice Bob Charlie Bob Alice Here is the original code in Python: def all_permutations(permList, nameList): # TODO: Implement method to create and output all permutations of the list of names. pass if __name__ == "__main__": nameList = input().split(' ') permList = [] all_permutations(permList, nameList)
- The Binary Search algorithm works by testing a mid-point, then eliminating half of the list. In this exercise, you are going to take our binary search algorithm and add print statements so that you can track how the search executes. Inside of the recursive binary search function, add print statements to print out the starting, ending, and midpoint values each time. Then as you test a value, print out the results, either too high, too low, or a match. Sample Output Starting value: 0 Ending value: 9 Testing midpoint value: 4 Too high! Starting value: 0 Ending value: 3 Testing midpoint value: 1 Too low! Starting value: 2 Ending value: 3 Testing midpoint value: 2 Match! public class BinaryExplorer { public static void main(String[] args) {int[] testArray = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; binaryRec(testArray, 8, 0, testArray.length - 1); } /*** Add Print statements to the binaryRec method:* * Print Starting, ending, and midpoint values.* * Print when you find a match* * Print if you are…The Binary Search algorithm works by testing a mid-point, then eliminating half of the list. In this exercise, you are going to take our binary search algorithm and add print statements so that you can track how the search executes. Inside of the recursive binary search function, add print statements to print out the starting, ending, and midpoint values each time. Then as you test a value, print out the results, either too high, too low, or a match. Sample Output Starting value: 0 Ending value: 9 Testing midpoint value: 4 Too high! Starting value: 0 Ending value: 3 Testing midpoint value: 1 Too low! Starting value: 2 Ending value: 3 Testing midpoint value: 2 Match!Write a recursive Java function displayOutIn that displays two items from an array list at one instance from out-to-in. until one or last two items displayed and the process stops. For example, given array A = {15, 74, 106, 10, 9, 86, 34} the displayOutIn function displays the following: 15, 34 74, 86 106, 9 10
- Fibonacci numbers are a sequence of integers, starting with 1, where the value of each number is the sum of the two previous numbers, e.g. 1, 1, 2, 3, 5, 8, etc. Write a function called fibonacci that takes a parameter, n, which contains an integer value, and have it return the nth Fibonacci number. (There are two ways to do this: one with recursion, and one without.)java Write a recursive function with two parameters: an array of ints and the number of elements in the array. The function will return the sum of all positive values in the array. Do not add any negative array elements to the sum. You can add another parameter to the function if you wish.Write a recursive function that finds the number of occurrences of a specified character in a list. You need to define the following two functions. The second one is a recursive helper function.def count(chars, ch):def countHelper(chars, ch, high):Write a test program that prompts the user to enter a list of characters in one line, and a character, and displays the number of occurrences of the character in the list.