Σ00)=E(+1) + Ex(+2) (v + 2) + & 6+ ... Given that, for ¹2C¹60₂: 0₁ = 1354.07 cm ¹, ₂ = 672.95 cm ¹,03 = 2396.30 cm-¹, X11-3.10 cm.x22 = 1.59 cm, ¹.x22 = 1.59 cm ¹₁x33 = -12.50 cm-¹, X12 = -5.37 cm¹, X13 = -19.27 cm¹, x23 = -12.51 cm-¹, V₂ is a bending mode 8220.62 cm-¹ G(v₁1) and G(v₂ = 2) are two levels calculate the wavenumbers of the v₁ = 1 level and the v₂ = 2 (₂ = 0) level. The resulting levels both have 2 symmetry and, because of this and the fact that they would otherwise be close together, they interact by a process called Fermi resonance. As a result they are pushed much further apart. (0₁, 02, and 3 are equilibrium values corresponding to the vibrations V₁, V₂, and v3).

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Given that, for 12c"0;:
01 = 1354.07 cm, 02 = 672.95 cm, 03 = 2396.30 cm,
X11 = - 3.10 cm,x22 = 1.59 cm-
*33 = -12.50 cm-.
%3D
%3D
X12 - 5.37 cm-, x13 = -19.27 cm, 23 = -12.51 cm,
v2 is a bending mode
G(v1 = 1) and G(v2 = 2) are two levels
%3D
822 = - 0.62 cm-1
calculate the wavenumbers of the v = 1 level and the 2 (2 = 0) level. The resulting
levels both have Et symmetry and, because of this and the fact that they would otherwise
be close together, they interact by a process called Fermi resonance. As a result they are
pushed much further apart. (, 02, and oz are equilibrium values corresponding to the
vibrations v, V2, and v3).
Transcribed Image Text:Σ + Σ Given that, for 12c"0;: 01 = 1354.07 cm, 02 = 672.95 cm, 03 = 2396.30 cm, X11 = - 3.10 cm,x22 = 1.59 cm- *33 = -12.50 cm-. %3D %3D X12 - 5.37 cm-, x13 = -19.27 cm, 23 = -12.51 cm, v2 is a bending mode G(v1 = 1) and G(v2 = 2) are two levels %3D 822 = - 0.62 cm-1 calculate the wavenumbers of the v = 1 level and the 2 (2 = 0) level. The resulting levels both have Et symmetry and, because of this and the fact that they would otherwise be close together, they interact by a process called Fermi resonance. As a result they are pushed much further apart. (, 02, and oz are equilibrium values corresponding to the vibrations v, V2, and v3).
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