Set P₁ = 7 kN, P₂ = 8 kN . (Figure 1) Figure 4m B E 4m 4 m 6 m D
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- The figure below depicts the tire, axle, and gear of a large tractor. The entire structure is in mechanical equilibrium. Bearings support the rotating axle at points A and C attached to the tractor's frame. A force FD = 5000 lb is applied in the -z direction at point G of a gear with a 3-in radius. The force W = 1000 lb in the +z direction represents a normal force resulting from the weight of the tractor. The force Q acting in the +x direction, represents the traction force between the tire and the ground. The wheel, axle, and gear assembly weigh 150 lb with center of gravity at point D, which lies on the y axis with coordinate yp = -18 in. Points A, C, D (not seen in the figure), and E lie in the yz plane. Point G lies in the xy plane. Questions & Analysis: (a) Draw the FBD for the wheel, axle, and gear assembly if the bearings at A and B resist moments and the bearing at A is a thrust bearing. Label all unknowns. (b) Is the assembly statically determinate or statically…Forces of F1=15 kN in the z direction from the B point, F2=10 kN in the z direction from the C point and F3=10 kN in the y direction act on the arm in the figure. The lengths of the arm are also given as L1=0.15 m and L2=0.16 m. The radius r in the a-a section taken over the arm is r=0.2 m and it is desired to determine the stress state at point A. The shear modulus of the sleeve material is G=65 Gpa. According to this; WRITE YOUR RESULTS IN THE BOXES WITHOUT THE UNITS IN kPa. a) Find the shear stress due to the shear force at point A. Response b) Find the shear stress due to the torsional moment at point A. Response c) Find the total shear stress at point A. Response d) Find the normal stress due to the normal force at point A. Response e) Find the normal stress due to the bending moment at point A. Response f) Find the total normal stress at point A. ResponseForces of F1=8 kN in the z direction from the B point, F2=5 kN in the z direction from the C point, and F3=10 kN in the y direction act on the arm in the figure. The lengths of the arm are also given as L1=0.15 m and L2=0.16 m. The radius r in the a-a section taken over the arm is r=0.2 m and it is desired to determine the stress state at point A. slip of sleeve material module is G=75 Gpa. Accordingly, a) Find the shear stress due to the shear force at point A. b) Find the shear stress due to the torsional moment at point A. c) Find the total shear stress at point A. d) Find the normal stress due to the normal force at point A. e) Find the normal stress due to the bending moment at point A. f) Find the total normal stress at point A.
- For the figure show find the value of A by using just (EFx) F=4 kN A 0=60° 0=60° A=4 kN A=6 kN A=5 kN None of them4-61 Change the force F to {200i + 400j -700k}5) In the figure shown below the person pulls the cable vertically downward to move box number 1, find the amount of tension in the cable at the start of the motion, assuming W1=W2= 500 N, µ1=0.3 and p2=0.6. 2m
- Q1: Draw just the Free Body Diagram of the following figures. D Figure (1) Figure (2) Figure (3) T 30° 45° 60° - Figure (4) Figure (5) 26 kN 250 N 30 13 12 30 0.15 m 0.4 m B. 0 m 2 m 4 mThe forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β = 30° with the horizontal axis . Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=22 cm , b =33 cm and c= 60 cm , respectively . A force of F= 120 N, which makes an angle of γ=30° with the vertical from the point C, acts on the athlete's hand . Weight of the athlete's armW= 80 N. The direction of application of the Fm muscle force makes an angle of α=20° with the longitudinal axis of the arm. According to this; a) Calculate the muscle strength F M b) Calculate the angle θ of the joint reaction force F J with the horizontal.…The forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β=15° with the horizontal axis. Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=20 cm, b =33 cm and c= 65 cm, respectively. The athlete's hand is exerted by a force of F= 150 N, which makes an angle of γ=30° with the vertical from the point C. The weight of the athlete's arm is W= 100 N. The direction of application of the Fm muscle force makes an angle of α=25° with the longitudinal axis of the arm. According to this; a) Calculate the FM muscle strength. b) Calculate the angle θ of the FJ joint reaction force with the horizontal.…
- L3 =440 B M1 IC M2 L4 = 510 M1= 81 M2-48 L3 (mm) L4 (mm) 80 mm 120 mm а-а -b-b Geometric situation in figure 4, which consists of small dimensions in figure 4 The system is made of steel structure and is under the influence of torsional moments. your rod angle AB 80mm; Angle BC is 120 mm and the sliding unit of the steel G= 80000 MPa. a- Draw the torsional moment diagram of the rod. b- Calculate the maximum shear stress that will develop in the system. C- Calculate the relative rotational value of point C with respect to point A.For the given figure shown, a = 6 m, b = 9 m, c = 3 m, r = 7m. h bQ1 A horizontal beam BC is subjected to uniformly distributed load, w and at the same time it is supported at end B by a column AB (diameter of 50 mm) as shown in Figure Q1. Assume that all bars are pin-connected. (а) Sketch a complete Free Body Diagram (FBD) for the beam with clearly shows the all forces/moment involved. From the FBD, determine the equation of force for member AB, PAB and also the critical force, Per,x and Pery associated with member АВ.