Shear stress on the X face in y direction . The bhorse D sfate f storess.at a poitt i giuen by.t0720 MN/m²f30to[0]=20The shors सज्प क हिसर४ म-वiबeीक की Csame point is Hoen equat to?

Given; Three- dimensional state of stress at a point is given by; Find shear stress on the x- face…

Answered: Shear stress on the X face in y…

Engineering

Mechanical Engineering

Shear stress on the X face in y direction .

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

f jon The pilot of a crippled jet was able to control his plane by throttling the two engines. The plane has a weight of 17000 lb and a radius of gyration of kg = 4.7ft about the mass center G. Originally the plane is flying straight at a speed of 1200 ft/s. Neglect the effects of 5000 lb as shown, determine: drag and the loss of fuel. If the thrust in each engine is altered to T₁ = 800 lb and T₂ Remark: The counterclockwise sense is the positive sense. 1.25 ft T₂ 1.25 ft T₁ 1:21:02 7
Please solve this question queckly
3) ol Cag. - thing shownin Fig.2.2 the tetal hand loss ChL) from Pant 1 to pant Lis soft, hind the presune atpont 2 0.84)s Hlawnginapipeyender the Gand Port 1 D,z 6in こ 10.70 At Point 2 Dzz 9in Pz z 2 4.00Pt Reference detum
valg, (21535mm 1.15 The pressure difference, Ap, across a partial blockage in an artery (called a stenosis) is approximated by the equation μV Ap - K. 4 + K.(A-1) pv² = K₂ A s.r to zogy nish190 32\V as bonb dignol a 3 basiy noft where V is the blood velocity, u the blood viscosity (FL-2T), p the blood density (ML), D the artery diameter, Ao the area of the unobstructed artery, and A, the area of the stenosis. Determine the dimensions of the constants K, and K. Would this equation be valid in any system of units?
M-(1zy.z– ly.y) + M,(1;.z – lzy-y) Iz.ly - Izy loa - Ol dy Pr My Formüller; o =- • 01 • Ox 2 Pr Ox + dy o - Ga0, + o3 < of , Jort • 02 2t Tmaks 2 2 2 w Oz + Oy Tc d?y M(x) - a.2 Omaks.min + Ty , 8 = aAT, 1 =. EI (**-%)* + r3y · tejp - MalanıcpXc, @pc EI Malanipc EI A (0x Tầy • tc/p Tmaks 2 В ƏM Map dx, Per vQ It EI Calculate the reaction at support A for the beam and loading shown in the figure. w = 5 N/mm and L = 1.2m 2250 N 3520 N 1930 N 2680 N 3210 N
11:19 Edit Done Q2: Find the horizentai and vertical component of the torce 200 N in figer Figerm More
Fo = S0N, w= 20 haldls. - 4. Find Eom Sur the folluwing oysjem. K, = - lovu N/m Kq'n 500 N/m, C=500 Na3/m m- lo kg, r:5 em, Jo I kg-m Fo sinwL x(4)
H.w (2):As a train acceleates uniformaly it passes su ccessive Kito meter marks white traveling at velocities ot z mis andd somis: traveling Determine the train's velocity whenit passes time it tak. the next kitometer mark and the to travel the 2- Km distance-
M-(!zy.2– ly.y) + M,(:.2 – Izy .Y) Iz.ly – Izy Pr My Formüller; o -- • Ox = t Pr Oz + Øy Gort Tmaks 2t 2 2 2 Oz + Oy + Tc d?y _M(x) Omaks.min + Ty, E = aAT, T = I dx? El Malanıcp¾c , @pjc Malanıpc El Tmaks = EI 2. ƏM -dx. Pgr M VQ EI It Both ends of the fixed (fixed) rod were mounted at 0 °c. Calculate the minimum diameter of the bar so that there is no buckling in the bar when the ambient temperature rises to 100 °C? a= 12.10-6/°C, L= 5 m 13,069 cm 10,024 cm 15,034 cm 18,038 cm 11,026 cm
PROBIEM 1 AssoHE A BONDARY LAYER FOR A Fluid OVER A F|AT PIATE CAN BE APPROKIMATED BY WHERE U= CONSTANT is THE FREE STREAM VelociTy AND S. S(x) is THE THICKNESS Of THE BON DARY LAYER. ) WHICH BOUNDARY CONDITIONS ARE SATISFIED AND WHICH ONES ARE NOT ? 2) calculATE S* AND g* 3) WRITE AN EXPRESSION FOR THEe wall STRESS, AS A PUNCTION OF U, S AND . WHERE Y is THE Visaosire OF THe Fluid. INDICATE THE DIRECTION OF THE STRESS. 4) OBTAIN AN EQJATION FOR S«) FROM THE MOMENTUM INTEGRAI EQUATION 5) OBTAIN S«)
rerce D6 =blank Dimetr Yedaction Fn =0015 Y(Pi-CDp Ev-vam velocity PP- Panch Diametr FELt Ye Sreching force woling force drawing foreo 2. 25 ower Kx=0.98+o.02 Rd=die corner vadus mui die shape facArin extrustion -Lentn tthicknes YA=Stess ) Dirct on 1 The data given in Table Q1(a) corresponds to a cold heading operation performed to make square head on a steel bolt. Figure Q1(a) shows the dimensions of the bolt to be produced. Strength coefficient for the steel Table Q1(a) Strain hardening exponent 550 MPa Coefficient of friction at the die-work interface- 0.21 Thickness of wire stock out of which the bolt is made 0.16 Final length of the bolt. 10 mm 120 mm Compute: (i) The length of stock must project out of the die in order to provide sufficient volume of material for this upsetting operation. (ii) The total number of bolts that can be made out of 6 m rod (wire stock) (iii) The maximum force that the punch must apply to form the head 5 mm 10 mm 15 mm Figure Q1(a)
igure, PROBLEM 509 In the figure shown, determine the maxımum value of the applied force P to impend motion on the 2KN wedge if the angle of fnction for all contact surfaces is 15°. Figure, 2-KN WEDGE 1000-KN BLOCK 750