SITUATION 2: From the following data of a given sieve analysis: Sieve No. # 4 #8 #10 # 25 #60 #100 #200 (mm) 4.76 2.38 2.0 0.71 0.25 Opening Percent passing 90 64 58 30 22 10 0.149 0.074 4 9. Determine size(D10). а. 0.20 C. 2.0 the effective grain b. 0.15 d. 0.09
SITUATION 2: From the following data of a given sieve analysis: Sieve No. # 4 #8 #10 # 25 #60 #100 #200 (mm) 4.76 2.38 2.0 0.71 0.25 Opening Percent passing 90 64 58 30 22 10 0.149 0.074 4 9. Determine size(D10). а. 0.20 C. 2.0 the effective grain b. 0.15 d. 0.09
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![SITUATION 2:
From the following data of a given
sieve analysis:
Sieve
No.
# 4
Opening Percent
(mm)
4.76
2.38
2.0
0.71
0.25
0.149
0.074
passing
90
#8
#10
#25
# 60
#100
# 200
64
58
30
22
10
4
9. Determine
size(D10).
а. 0.20
с. 2.0
10. Determine Cu.
а. 10
C. 20
the effective grain
b. 0.15
d. 0.09
b. 15
d. 5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc47aba34-af98-41b2-a1c3-02fda0528a06%2Fda221436-5eef-4125-bb2f-a37457363931%2Flqw05f6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:SITUATION 2:
From the following data of a given
sieve analysis:
Sieve
No.
# 4
Opening Percent
(mm)
4.76
2.38
2.0
0.71
0.25
0.149
0.074
passing
90
#8
#10
#25
# 60
#100
# 200
64
58
30
22
10
4
9. Determine
size(D10).
а. 0.20
с. 2.0
10. Determine Cu.
а. 10
C. 20
the effective grain
b. 0.15
d. 0.09
b. 15
d. 5
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