Solve the following system of equations using the Gaussian algorithm with column pivoting: a + 2b + c + 3d = 1 2a + 5b + 3c + d = 0 a + 6b + 2c + 2d = 1 a + 4b + c + d = 0. I know I have to switch first line and 2. Since the "2" in the first column is the new pivotelement. I am struggling with what to do afterwards. I know the solution is supposed to be: a= -1,b=0,c=1/2,d=1/2 How do I get there?
Solve the following system of equations using the Gaussian algorithm with column pivoting: a + 2b + c + 3d = 1 2a + 5b + 3c + d = 0 a + 6b + 2c + 2d = 1 a + 4b + c + d = 0. I know I have to switch first line and 2. Since the "2" in the first column is the new pivotelement. I am struggling with what to do afterwards. I know the solution is supposed to be: a= -1,b=0,c=1/2,d=1/2 How do I get there?
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.7: Puzzle Problems
Problem 32P
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Solve the following system of equations using the Gaussian algorithm with column pivoting:
a + 2b + c + 3d = 1
2a + 5b + 3c + d = 0
a + 6b + 2c + 2d = 1
a + 4b + c + d = 0.
I know I have to switch first line and 2. Since the "2" in the first column is the new pivotelement.
I am struggling with what to do afterwards.
I know the solution is supposed to be:
a= -1,b=0,c=1/2,d=1/2
How do I get there?
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