Solve the initial boundary value problem for the given wave equation: Utt = 49ur, 0 0 %3D u(0, t) = u(3,t) =0, 1> 0 u(2, 0) =4 sin(2a) - 7 sin(5Ta), 0 < a <3 (2,0) = 14 TSin(47), 0< a < 3 Your Answer:
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- Show that the function Z = sin(wct)sin(wx) satisfies the wave equationPlease short steps and final answer. Solve the wave equation using Fourier Transform: o'u ou - c0 0 %3D -12x utx, 0) = H(x)e %3D u,(x, 0) = 0. Oa. u (x, t) = Real sin wt (12+iw) %3D 2 я Ob. 1 iwx u (x,t) Real cos wt dw (12+iw) Oc. iwx u (x,1) Real sın wt %3D w (12+iw) Od. 1 u (x,1) = Real cos wt w (12+iw) Oe correct ancueSolve the inhomogeneous wave equation on the real lineUtt − c2Uxx = sin x, x ∈ RU(x, 0) = 0, Ut(x, 0) = 0.Explain what theory you are using and show your full computations.
- for wave equation, seperation of vairables u(x,t)=X=(x)T(t)Solve the following wave equation using finite difference method. 4fxx = ftt - Given: f(0, t) = 0 and f(1, t) = 0 f(x, 0) = ft(x, 0) = 0 sin(x) + sin(2x) (Ref: Hyperbolic Equation)a2u satisfies the wave equation əx² -n a²u Verify that U(x, t) = e¬Vkt cos\ax %3D k at2
- Which of the following is most suitable solution for wave equation = c2? %3D at2 ax2 .(a) y = (AeP* + Be-P*)(Ce pt + De ept) (b) y = (Acos px + Bsin px)(Ccos cpt + Dsin cpt) (c) y = (Ax + B)(Ct + D) (d) y = (Aepx + Be-px)(Cep*t + De-ep*r) O a O b O c O d2. The position vector of a particle is given by r(t)= (2 cos t sin t)i +(cos^2 t - sin^2 t)j + (3t)k If the particle begins its motion at t = 0 and ends at t = pi, find the difference between the length of the path traveled and the distance between start position and end positionii. Find parametric equations for the Line through (7, 5) and (-5, 7) 7. Calculate dy/dx at the point indicated: f(0) = (7tan 0, cos O), 0=a/4
- The graph of f (θ) = Acos θ + B sin θ is a sinusoidal wave for any constants A and B. Confirm this for (A,B) = (1, 1), (1, 2), and (3, 4) by plotting f .If r(t) = cos(7t)i + sin(7t)j – 3tk, compute the tangential and normal components of the acceleration vector. COS Tangential component ar(t) Normal component an(t) =Solve using wave equation: u(0, t) = u(π, t) = u(x, 0) = 0, du/dt | t = 0 = sin(x)