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Solve these recurrence relations together with the initial conditions given. Arrange the steps to solve the recurrence relation an = an - 2 for n ≥ 2 together with the initial conditions a = 5 and a1 = -1 in the correct order. Rank the options below. +α2 5=α1+ -1=-α1 + α2 2 − 1 = 0; r = −1, 1 an = α1(−1)" + α21” = α1(−1)^ + α2 α13 and a2 = 2 Therefore, an = 3 ⋅(-1)+2. ་ ་ Solve these recurrence relations together with the initial conditions given. Match the steps (in the right column) to their corresponding step numbers (in the left column) to solve the recurrence relation an=-6an-1-9an - 2 for n ≥ 2 together with the initial conditions a0 = 3 and a₁ = −3. Step 4 2 Step 3 3 Step 1 4 Step 2 Match each of the options above to the items below. The characteristic equation and its roots are 12 + 6r+ 9 = 0 and r = −3, −3, respectively. The general solution is an = α₁(-3)" + α2n(-3)". Using initial conditions, 3 = α1 and −3 = −3α1 – 302 After solving, α1 = 3 and a2 = −2. Therefore, an = 3. (-3)" -2n(-3)" = (3 - 2n)(-3)".

Solve these recurrence relations together with the initial conditions given. Arrange the steps to solve the recurrence relation an = an - 2 for n ≥ 2 together with the initial conditions a = 5 and a1 = -1 in the correct order. Rank the options below. +α2 5=α1+ -1=-α1 + α2 2 − 1 = 0; r = −1, 1 an = α1(−1)" + α21” = α1(−1)^ + α2 α13 and a2 = 2 Therefore, an = 3 ⋅(-1)+2. ་ ་ Solve these recurrence relations together with the initial conditions given. Match the steps (in the right column) to their corresponding step numbers (in the left column) to solve the recurrence relation an=-6an-1-9an - 2 for n ≥ 2 together with the initial conditions a0 = 3 and a₁ = −3. Step 4 2 Step 3 3 Step 1 4 Step 2 Match each of the options above to the items below. The characteristic equation and its roots are 12 + 6r+ 9 = 0 and r = −3, −3, respectively. The general solution is an = α₁(-3)" + α2n(-3)". Using initial conditions, 3 = α1 and −3 = −3α1 – 302 After solving, α1 = 3 and a2 = −2. Therefore, an = 3. (-3)" -2n(-3)" = (3 - 2n)(-3)".

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.6: The Algebra Of Matrices
Problem 41E
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Solve these recurrence relations together with the initial conditions given. Arrange the steps to solve the recurrence relation an = an - 2 for n ≥ 2 together with the initial conditions a = 5 and a1 = -1 in the correct order. Rank the options below. +α2 5=α1+ -1=-α1 + α2 2 − 1 = 0; r = −1, 1 an = α1(−1)" + α21” = α1(−1)^ + α2 α13 and a2 = 2 Therefore, an = 3 ⋅(-1)+2. ་ ་
Transcribed Image Text:Solve these recurrence relations together with the initial conditions given. Arrange the steps to solve the recurrence relation an = an - 2 for n ≥ 2 together with the initial conditions a = 5 and a1 = -1 in the correct order. Rank the options below. +α2 5=α1+ -1=-α1 + α2 2 − 1 = 0; r = −1, 1 an = α1(−1)" + α21” = α1(−1)^ + α2 α13 and a2 = 2 Therefore, an = 3 ⋅(-1)+2. ་ ་
Solve these recurrence relations together with the initial conditions given. Match the steps (in the right column) to their corresponding step numbers (in the left column) to solve the recurrence relation an=-6an-1-9an - 2 for n ≥ 2 together with the initial conditions a0 = 3 and a₁ = −3. Step 4 2 Step 3 3 Step 1 4 Step 2 Match each of the options above to the items below. The characteristic equation and its roots are 12 + 6r+ 9 = 0 and r = −3, −3, respectively. The general solution is an = α₁(-3)" + α2n(-3)". Using initial conditions, 3 = α1 and −3 = −3α1 – 302 After solving, α1 = 3 and a2 = −2. Therefore, an = 3. (-3)" -2n(-3)" = (3 - 2n)(-3)".
Transcribed Image Text:Solve these recurrence relations together with the initial conditions given. Match the steps (in the right column) to their corresponding step numbers (in the left column) to solve the recurrence relation an=-6an-1-9an - 2 for n ≥ 2 together with the initial conditions a0 = 3 and a₁ = −3. Step 4 2 Step 3 3 Step 1 4 Step 2 Match each of the options above to the items below. The characteristic equation and its roots are 12 + 6r+ 9 = 0 and r = −3, −3, respectively. The general solution is an = α₁(-3)" + α2n(-3)". Using initial conditions, 3 = α1 and −3 = −3α1 – 302 After solving, α1 = 3 and a2 = −2. Therefore, an = 3. (-3)" -2n(-3)" = (3 - 2n)(-3)".
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