T Two capacitors are connected in series as shown below. The nominal capăcitances are C = 110µFand C, = 60µF, respectively. Each capacitor has a 3% uncertainty in the measured value. Find' the overall nominal capacitance C for the given circuit and the propagated uncertainty in Ç. It is known that C
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- During an experiment to verify Ohm's law, the voltage supplied and the current through a circuit are measured. [Voltage is measured in Volt (V) and current in Ampere (A)]. V www R A Battery The measured value of the current is I = 2.8 ± 0.1 A and that of the voltage is V = 18 ± 0.4 V. The resistance of the circuit %3D %3D (in Q) can be calculated using the formula, R =V/I, Calculate the, a) Resistance (in Q) = b) Fractional uncertainty in the resistance = c) Absolute uncertainty (in 2) in the resistance=sq 4. Maximum surface resistance. Consider a square sheet of side L, thickness d, and electrical resistivity p. The resistance measured between opposite edges of the sheet is called the surface resistance: R = pL/ Ld = p/d, which is independent of the area of the sheet. (R is called the resistance per square and is expected in ohms per square, because p/d has the dimensions of ohms.) If we express p by p=m/ne²t, then Rq=m/ndet. Suppose now that the minimum value of the collision time is determined by scattering from surfaces of the sheet, so that Td/v, where v is the Fermi velocity. Thus the maximum surface resistivity is Rmvp/nd²e². Show for a monatomic metal sheet one atom thickness that sq Rħ/e² = 4.1k, where lkn is 10³ ohms. sqQUESTION 8 Find the uncertainty in a calculated electrical potential difference from the measurements of current and resistance. Electric potential difference depends on current and resistance according to this function V(I,R) = IR. Your measured current and resistance have the following values and uncertainties I = 2.4 Amps, 81 = 0.2 Amps and R = 29.5 Ohms and SR = 0.6 Ohms. What is the uncertainty in %3! %3D the , SV ? Units are not needed in your answer.
- The voltage V (volts), current I (amperes), andresistance R (ohms) of an electric circuitare related by the equation V = IR. Suppose that V is increasing atthe rate of 1 volt/sec while I is decreasing at the rate of 1/3 amp/sec. Let t denote time in seconds. What equation relates dR/dt to dV/dt and dI/dt?What is the current read by the ammeter in the circuit below? Let R1 = 1 kiloohm, R2 = 2 kiloohm, R3 = 3 kiloohm, and the emf of the ideal source is 5 volts. Input R1, R2, and R3 for resistors R1. R2. and R3 respectively. Input E for the emf E. Use context clues to figure out if you need to input a numerical value, varioble, word, etc. All numerical answers should be in three significant figures. R1 R2 R3 (A) First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: 1= v R Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is in milliamperes) 1 = eeec0os Similarly the current across R2 is: mAP For a given load resistance R, = 4.7 ohm, the power transfer efficiencies 7 P load of total a de voltage source and a de current source with internal resistances R, and R,, respectively, are equal. The product R,R, in units of ohm (rounded off to one decimal place) is
- You plotted a graph of current vs. voltage and found the slope of the best fit line is m± Am = 4.69 ± 1.79 Amps/Volt. The resistance can be calculated from the slope by knowing: R = 1 m The fractional uncertainty in the slope is equivalent to the fractional uncertainty in the resistance: AR R = Am m Calculate the uncertainty in the resistance, AR in units of (ohms), then enter the raw value (no units) into the box below. Round to two decimal places. AR=Ohm's law for electrical circuits like the one shown in the figure states that V = RI. In this equation, V is a constant voltage, I is the current in amperes, and Ris the resistance in ohms. Your firm has been asked to supply the resistors for a circuit in which V will be 240 volts and I is to be 20±0.2 amp. In what interval does R have to lie for I to be within 0.2 amp of the value I, = 20? R. To what interval must R be held to meet the requirements for the resistance? ohmsThe voltage V (volts), current I (amperes), andresistance R (ohms) of an electric circuitare related by the equation V = IR. Suppose that V is increasing atthe rate of 1 volt/sec while I is decreasing at the rate of 1/3 amp/sec. Let t denote time in seconds. What is the value of dI/dt?
- Ex. 14 : A potentiometer wire has a length of 4 m and resistance 42. What resistance must be connected in series with the potentionmeter wire and a cell of e.m.f. 2V having internal resistance 20 to get a potential drop of 10 3 V/cm along the wire ?During an experiment to verify Ohm's law, the voltage and resistance of a circuit are measured. [Resistance is measured in Ohm (2) and voltage in Volts (V)]. www R A +, + Battery The measured value of the voltage is V = 9.8 ± 0.4 V and that of the resistance is R = 15 ± 0.4 Q. The current through the circuit (in Ampere (A)) can be calculated using the formula, I =V/R. Calculate the, a) Current (in Ampere) = b) Fractional uncertainty in the current = C) Absolute uncertainty (in Ampere) in the surrentBy measuring the currents and times and then draw the current vs time graph using the measurement at the lab for ε =8 V, R=1M Ω and C=60μF. What is the current at t=50 s?