Take longitudinal strain 0.02
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- A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The wire is made of a copper alloy having a stress-strain relationship that may be described mathematically by =18,0001+30000.03(=ksi) in which is nondimensional and has units of kips per square inch (ksi). (a) Construct a stress-strain diagram for the material. (bj Determine the elongation, of the wire due to the Forces P. (c) IF the forces are removed, what is the permanent set of the bar? (d) If the forces are applied again, what is the proportional limit?Determine the strain energy per unit volume (units of psi) and the strain energy per unit weight (units of in ) that can be stored in each or the materials listed in the accompanying table, assuming that the material is stressed to the proportional limit. DATA FOR PROBLEM 2.7-5 Material Weight Density (lb/in3) Modulus of Elasticity (ksi) Proportional Limit (psi) Mild sleel 0.284 30,000 36,000 Tool steel 0.284 30,000 75,000 Aluminum 0.0984 10,500 60,000 Rubber (soft) 0.0405 0.300 300If the longitudinal strain is 0.003 and the poisson's ratio is 0.3, calculate the transverse strain.
- In uniaxial loading the poisson's ratio is 0.30 and the strain in the x- direction is 250 x 10^-6. What is the strain in the z- direction?A cube has sides that are initially 80 mm and is subjected to stresses of 40 MPa (tensile), 30 MPa (compressive) and 70 MPa (tensile) in the x, y and z -directions, respectively. Calculate (a) the strains in these directions, (b) the changes in dimensions, (c) the volumetric strain and (d) the change in volume.Take E = 214 GPA and Poisson’s ratio = 0.33.A rod is subjected to a uni-axial load within linear elastic limit. When the change in the stress is 200 MPa, the change in the strain is 0.001. If the Poisson's ratio of the rod is 0.3, the modulus of rigidity (in GPa) is
- A bar produces a lateral strain of -70 x 10-5 when subjected to tensile stress of magnitude 400 MPa along the axial direction. What is the elastic modulus of the material, if the Poisson's ratio is 0.3?When a brass rod of diameter 2 mm is subjected to a tension of Sx10 N, the diameter changes by 3.6x104 cm. Calculate the Poisson's ratio for brass given that the Elastic modulus for the brass is 9x100 N/m and the longitudinal strain for the brass rod is1.96x103 useful equation: Poissons ratio = Lateral strain / Longitudinal strain O 0.63 O 031 O 1.11 O 0,922. An elastic rod of 25mm in diameter, 200mm long extends by 0.25mm under a tensile load of 40kN. Find the intensity of stress, the strain and the elastic modulus for the material of the rod.
- A rod is subjected to a uni-axial load within linear elastic limit. When the change in the stress is 200 MPa, the change in the strain is 0.001. If the Poisson's ratio of the rod is 0.3, calculate the modulus of rigidity.A rod is subjected to a uniaxial load within linear elastic limit. When the change in the stress is 200 MPa, the change in the strain is 0.001. Calculate the modulus of rigidity if the poisson's ratio is 0.3.A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a load of 8.00 kg is hung on its end. Find the stress, the strain, and the Young's modulus for the material of the wire.