The capacitor in the circuit is initially uncharged and the switch S is suddenly closed at t=0. Find the current on resistor R: at to Take R₁-4R and R 3R. A) = B) 6 C) 25 D) E) SIA R₂ FE R₁
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- You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.An AC circuit contains a 24 resistor, a 15.9-mH inductor, and a 13.3F capacitor connected in parallel. The circuit is connected to a 240-V, 400-Hz power supply. Find the following values. XL=XC=IR=AIL=AIC=AP=WVARsL=VARsC=IT=AVA=PF=%=The figure below shows a simple RC circuit with a 3.30-μF capacitor, a 4.40-M resistor, a 9.00-V emf, and a switch. What are the following exactly 9.00 s after the switch is closed? (a) the charge on the capacitor 13.7204 UC (b) the current in the resistor 0.0110522 x Your response is off by a multiple of ten. HA (c) the rate at which the capacitor is storing energy μW (d) the rate at which the battery is delivering energy μW
- The current through a 50 mH inductor is given below. Use Ohm’s Law to find the voltage. Convert to polar form, find the impedance and complete the math, then convert back to the waveform at i1 = 7.5sin(2500t – 20°) mA and i2 = 5.9sin(200t + 40°) mAAn inductor and a resistor are in series with a sinewave voltage source. The frequency is set so that the inductive reactance is equal to the resistance. If the frequency is increased, then options: Voltage across the inductor= Source Voltage Voltage across the inductor> Voltage across the resistor Voltage across the inductor= Voltage across the resistor Voltage across the resistor > Voltage across the inductorCONSIDER THE CIRCUT BELOW.SUPPOSE V1=10V AND V2=1V BEFORE THE SWITCH IS CLOSED,WHAT IS THE COOMN VOLTAGE ACROSS THE CAPACITOR AFTER THE SWITCH CLOSED.
- Please explain this question properly A capacitor has a reactance of 40 when operated on a 50 Hz supply. Determine the value of its capacitance. In a series R–L circuit the p.d. across the resistance R is 12V and the p.d. across the inductance L is 5V. Find the supply voltage and the phase angle between current and voltage4. A RC series circuit is composed of a resistor of resistance 50 ohms and a capacitor of capacitance 100µF. It is suddenly disconnected from a source voltage of 12V. Determine the time it takes for the voltage across each element is equal and determine the rate of change in the current at this time.A 250-V circuit, consisting of a resistor, an inductor and a capacitor in series, resonates at 50 Hz. Thecurrent is then 1A and the p.d. across the capacitor is 500 V. Calculate (i) the resistance (ii) theinductance and (iii) the capacitance Answer:
- The total capacitance for this circuit is C₁ 5 F A. .035 farad. B. .06 farad. C. .026 farad. D. .0026 farad. C₂ 10 F C3 10 F What is the total capacitance of a circuit with three capacitors connected in series with the following values: C1 = .015 farad, C2 = .015 farad, and C3= .015 farad? A. 5 farad. B. .05 farad. C. .015 farad. D. .005 farad. What is the total capacitance of a circuit containing a .01 farad, a .015 farad, and a .001 farad capacitor, all connected in parallel?A series R–L–C circuit comprises a 5µF capacitor, a 4ohm resistor and a variable inductance L. The supply voltage is 10∠0◦ V at a frequency of 159.1 Hz. The inductance is adjusted until the p.d. across the 4 ohm resistanceis a maximum. Determine for this condition (a) the value of inductance, (b) the p.d. across each component and (c) the Q-factor of the circuit.In the circuit below, Find the voltage across the inductor at time t = 0.000909 s. The values are V1 = 146V, R = 4.4 ohms, L =0.02 henries