The chart below shows the first five successive ionizations of element M. What is the formula of the ionic compound formed when element M combines with the carbonate anion. enthalpy (kl/mol) 16000 14000 12000 10000 8000 6000 4000 2000 0 1 2 3 4 5 Successive ionization energies Click here if the image doesn't load. B O M₂(COsh ○ MCO ○ M₂CO O MICO₂h
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- f21 > Macmillan Learning Consider an ionic compound, MX3, composed of generic metal M and generic gaseous halogen X. • The enthalpy of formation of MX3 is AH = -889 kJ/mol. ⚫ The enthalpy of sublimation of M is AH sub 127 kJ/mol. • The first, second, and third ionization energies of M are IE₁ = 569 kJ/mol, IE2 1735 kJ/mol, and IE3 2683 kJ/mol. • The electron affinity of X is AHEA = -357 kJ/mol. (Refer to the hint). ⚫ The bond energy of X2 is BE = 241 kJ/mol. Determine the lattice energy of MX3. AH lattice= kJ/molCalculate the attraction and repulsion force between a pair of Ba2+ and S2- ions. Assume the ionic radius of Ba2+ and S2- are 0.143 nm and 0.174 nm respectively. Given, k = 9 x 109 Nm2C-2electron charge, e = 1.6 x 10-19 Cesc →> Docun X 77°F Mostly cloudy ? W 2 Argum X https://app.101edu.co 3+ Use Coulomb's law to calculate the energy in aJ of the following ions to their equilibrium ion-pair separation distance: Fe³+ with radius 55 pm and P3 with a radius of 212 pm. # Life: Th X 13 * 3 f4 $ 101 223.pd X M MyOpe X 4 f5 % Q 5 D21 Home X Feedbe X Archive | Login A1 f6 Question 6 of 35 6 E hp & 7 18 * 00 19 D W 1 4 ho
- Calculate the lattice energy of NaBr(s), given the following thermochemical equations, where A/E and AEA are ionization energy and electron affinity, respectively. Na(s)Na(g) AH = +107 kJ Na(g) Nat(g) + e A/E = +496 kJ -> 1/2 Br₂(g) → Br(g) AHf = +112 kJ - Br(g) + e¯ → Br¯(g) AEA = -325 kJ Na(s) + 1/2 Br₂(g) → NaBr(s) AH = -361 kJ ->> - -1401 kJ -751 kJ +29 kJ -29 kJ +751 kJWhich of the following combination of elements is the most reactive? Cs and I Na and Br Cs and Br K and IN Calculate the lattice enthalpy for RbCl. You will need the following information: Species A,H, kJ/mol Rb(e) RbCl() CI(g) Enthalpy of ionization for Rb(g) is 403.0 kl/mol; electron attachment enthalpy for Cl(g) is-349.0 kJ/mol Lattice enthalpy kJ/mol Submit Answer *** 1 43 E D 80.9 -435.4 121.3 Try Another Version 80 54 R F di a 25 2 item attempts remaining T G ‹6 P FA Y & 29 7 H 8 #7 U 8 Dil FA - 6 8 K
- Use the periodic table to order the following atoms from smallest (1) to largest (4) Al Ba P Ca6.941 mol atomic mass electronegativity 0.98 kJ 59.6 mol electron affinity kJ 520.2 mol ionization energy kJ 3.0 mol heat of fusion Does the following reaction absorb or release energy? O release O absorb (1) Li (g) + e Li(g) O Car be decided with the data given. Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above? O yes O no If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1): O k/mol Does the following reaction absorb or release energy? O release O absorb (2) Li(g) → Li (g) + e O Can't be decided with the data given. Is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above? O yes O no If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2): I kJ/mol4:25 1 ull 5G D Send a chat Be sure to answer all parts. Hint The American chemist Robert S. Mulliken suggested a different definition for the electronegativity (EN) of an element, given by IE, Solution Element EA kJ/mol kJ/mol Guided Solution IE, + EA EN = 1314 141 2 1680 328 where IE, is the first ionization energy and EA is the electron affinity of CI 1256 349 the element. Calculate the electronegativities of O, F, and Cl using the preceding equation and the data in the table. EN(O) = kJ/mol EN(F) = kJ/mol EN(CI) = kJ/mol Determine the electronegativities of these elements on the Mulliken and Pauling scales. (To convert to the Pauling scale, divide each EN value by 230 kJ/mol.) Mulliken EN(F) Mulliken EN(CI) Mulliken EN(0) Pauling scale = Pauling scale = Pauling scale = (Pauling EN(CI) = 3.0) (Pauling EN(O) = 3.5) (Pauling EN(F) = 4.0)
- Determine the second ionization energy of calcium (in kJ mol-1) from the given data (all in kJ mol-1): AH°[CaCl,(s)] = -796 AH¡[Ca(g)] = 178 AH°[CI(g)] = 122 First ionization energy of Ca(g) = 590 Electron affinity of Cl(g) = -349 Lattice enthalpy of CaCl,(s) = -2260 А 1150 В 1235 C 1093 D 121019 of 44 > © Macmillan Learning In the given three-dimensional molecular structure, the differently colored spheres represent different types of atoms. Write a molecular formula for this molecule. molecular formula: 4 R % 67 68 5 1 SPECIAL xº (g) ΔΣΩ λμπ X₁ X () 6 [] (s) Y (1) (aq) →>>> MacBook Pro The 11 7 U t CLR 8 K →>> 9 Rotate X You 9 Rotate Y ( 0 ☐C □H D Rotate Z 0 Zoom In P O Zoom Out Attempt A Label Atoms CSalt Formation & Formulas K(s) + Br₂ (8) K (s) Li (s) F2 (g) + F₂ + N₂ (8) Ca + Cl₂ (8) (s) Na 02 (8) (s) + Al (s) + Cl₂ (g) → potassium bromide potassium fluoride lithium nitride calcium chloride sodium oxide aluminum chloride 2 3 4 5 6 7 ΤΑ Using what you know about predicting ion charge, ionic bonding, and the criss-cross technique, write neutral salt product formulas for these synthesis equations. 2A 2 A ú Be 6.94 90122 12 Na Mg 22990 24.305 K C 34 39.00 40.078 44.956 37 87 Fr G B₁ 13291 137.33 charge 3B 4B 5B 6B 7B 8B 9B 10B IIB 12B 3 10 11 12 H (223) (236) 36 53-71 72 73 Hr Ta 74 178.49 180.95 183.84 88 99-103 104 105 P₂ Ra Rf Db Lanthanide series #Actinide series group A num 11 V 47367 50.942 51.996 54.938 43 & Nb Mo Tc Ru Rh Pd Ag Cd CSSE 85.468 87.62 88.906 91.224 92.906 95.95 (9) 75 191.07 102.91 106.42 10787 11241 114.82 118.71 121.76 127 60 17 78 10 81 14 Os Ir P A H₂ 186.21 190.23 192.22 195.08 196.97 20039 204.38 108 109 110 III 112 113 Bh Hs Mt Ds Ca Nh (270) Pb N Pa At…